Math Problem Statement

Suppose that a stock's price continues to increase at the rate of 5% per year. If the value of one share of this stock is ₹1000 at present, then find the value (in ₹) of one share of this stock two years from now. (Use the formula S = a(1 + r)^n, where r is the increase rate per year, n is the number of years from now, a is the present value of one share of the stock, and S is the value of one share of the stock after n years from now.)

Solution

To solve this problem, we use the formula:

S=a(1+r)nS = a(1 + r)^n

where:

  • a=1000a = 1000 (present value of one share of the stock),
  • r=0.05r = 0.05 (increase rate per year, as 5% is converted to decimal),
  • n=2n = 2 (the time in years).

Substituting these values into the formula:

S=1000×(1+0.05)2S = 1000 \times (1 + 0.05)^2

Calculating step-by-step:

  1. Calculate 1+r1 + r: 1+0.05=1.051 + 0.05 = 1.05

  2. Raise 1.051.05 to the power of 22: (1.05)2=1.1025(1.05)^2 = 1.1025

  3. Multiply by the initial value: S=1000×1.1025=1102.5S = 1000 \times 1.1025 = 1102.5

Therefore, the value of one share of the stock two years from now is ₹1102.5.

The correct answer is:

  • ₹1102.5

Would you like further details on this calculation, or do you have any other questions?


Here are 5 related questions you may find interesting:

  1. What would the value of the stock be after 5 years at the same growth rate?
  2. How does changing the growth rate to 6% impact the stock value after 2 years?
  3. What is the formula to calculate compound interest for different compounding periods?
  4. How would the answer change if the stock decreased by 5% annually instead?
  5. How do we calculate the effective annual growth rate when compounding monthly?

Tip: Understanding how to apply the compound interest formula is crucial for calculating investments or savings over time.

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Math Problem Analysis

Mathematical Concepts

Exponential growth
Compound interest

Formulas

S = a(1 + r)^n

Theorems

Compound interest theorem

Suitable Grade Level

Grades 9-12