Math Problem Statement

f(a+h)=

Solution

Given the function f(x)=4xf(x) = \frac{4}{x}, you are looking to evaluate the function at x=a+hx = a + h.

Substituting x=a+hx = a + h into the function f(x)f(x), we get:

f(a+h)=4a+hf(a+h) = \frac{4}{a+h}

This is the expression for f(a+h)f(a+h) when f(x)=4xf(x) = \frac{4}{x}.

Would you like further details on how this relates to other concepts, such as the difference quotient?

Here are five related questions:

  1. How would you compute the difference quotient f(a+h)f(a)h\frac{f(a+h) - f(a)}{h} for this function?
  2. What does the expression f(a+h)f(a+h) represent in the context of a function's rate of change?
  3. How does the limit of f(a+h)f(a)h\frac{f(a+h) - f(a)}{h} as hh approaches 0 relate to the derivative of f(x)f(x)?
  4. How would you interpret f(a+h)f(a+h) geometrically on the graph of f(x)f(x)?
  5. What is the significance of evaluating a function at a+ha + h in calculus?

Tip: Understanding the difference quotient is crucial, as it is the foundation for finding the derivative, which represents the rate of change of a function.

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Math Problem Analysis

Mathematical Concepts

Function Evaluation
Difference Quotient
Rate of Change
Derivative

Formulas

Function evaluation at x = a + h: f(a+h) = 4/(a+h)
Difference quotient: (f(a+h) - f(a)) / h

Theorems

Definition of derivative
Limit definition of derivative

Suitable Grade Level

Advanced High School