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The problem asks to compute \( \frac{f}{g}(-10) \), where the functions are given as:

- \( f(x) = x^2 - 5 \)
- \( g(x) = 12 - x \)

To solve \( \frac{f}{g}(-10) \), follow these steps:

1. **Calculate \( f(-10) \):**
   \[
   f(-10) = (-10)^2 - 5 = 100 - 5 = 95
   \]

2. **Calculate \( g(-10) \):**
   \[
   g(-10) = 12 - (-10) = 12 + 10 = 22
   \]

3. **Now compute \( \frac{f}{g}(-10) \):**
   \[
   \frac{f(-10)}{g(-10)} = \frac{95}{22}
   \]

So, the simplified answer is \( \frac{95}{22} \).

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### Related Questions:
1. How do you find the composition of functions \( f \circ g \)?
2. What happens if the denominator of a function operation is zero?
3. How would you simplify \( \frac{f(x)}{g(x)} \) for any given \( x \)?
4. Can \( f(x) \) and \( g(x) \) be defined piecewise, and how would that affect their operations?
5. How do you apply function division when both functions are polynomials?

**Tip:** Always check for undefined values in the denominator when performing division with functions.

Let f(x) = x^2 - 5 and g(x) = 12 - x. Perform the composition or operation indicated: (f/g)(-10).

Learn how to perform the function division (f/g)(-10) where f(x) = x^2 - 5 and g(x) = 12 - x. This problem covers function operations and composition in algebra. Suitable for high school students (Grades 9-12).

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