Math Problem Statement

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Find two functions f and g such that (f ◦ g)(x) = h(x) for exercises 65 to 72.

Solution

In the provided exercises (65–72), you are asked to find two functions f(x)f(x) and g(x)g(x) such that:

(fg)(x)=h(x)(f \circ g)(x) = h(x) This means f(g(x))=h(x)f(g(x)) = h(x), where h(x)h(x) is the given function. Let's go through each exercise to find such ff and gg functions.

65. h(x)=(2x+1)2h(x) = (2x + 1)^2

We can choose:

  • g(x)=2x+1g(x) = 2x + 1
  • f(x)=x2f(x) = x^2

This gives: f(g(x))=f(2x+1)=(2x+1)2=h(x)f(g(x)) = f(2x + 1) = (2x + 1)^2 = h(x)

66. h(x)=(1x)3h(x) = (1 - x)^3

We can choose:

  • g(x)=1xg(x) = 1 - x
  • f(x)=x3f(x) = x^3

This gives: f(g(x))=f(1x)=(1x)3=h(x)f(g(x)) = f(1 - x) = (1 - x)^3 = h(x)

67. h(x)=x243h(x) = \sqrt[3]{x^2 - 4}

We can choose:

  • g(x)=x24g(x) = x^2 - 4
  • f(x)=x3f(x) = \sqrt[3]{x}

This gives: f(g(x))=f(x24)=x243=h(x)f(g(x)) = f(x^2 - 4) = \sqrt[3]{x^2 - 4} = h(x)

68. h(x)=9xh(x) = \sqrt{9 - x}

We can choose:

  • g(x)=9xg(x) = 9 - x
  • f(x)=xf(x) = \sqrt{x}

This gives: f(g(x))=f(9x)=9x=h(x)f(g(x)) = f(9 - x) = \sqrt{9 - x} = h(x)

69. h(x)=1x+2h(x) = \frac{1}{x + 2}

We can choose:

  • g(x)=x+2g(x) = x + 2
  • f(x)=1xf(x) = \frac{1}{x}

This gives: f(g(x))=f(x+2)=1x+2=h(x)f(g(x)) = f(x + 2) = \frac{1}{x + 2} = h(x)

70. h(x)=4(5x+2)2h(x) = \frac{4}{(5x + 2)^2}

We can choose:

  • g(x)=5x+2g(x) = 5x + 2
  • f(x)=4x2f(x) = \frac{4}{x^2}

This gives: f(g(x))=f(5x+2)=4(5x+2)2=h(x)f(g(x)) = f(5x + 2) = \frac{4}{(5x + 2)^2} = h(x)

71. h(x)=(x+4)2+2(x+4)h(x) = (x + 4)^2 + 2(x + 4)

We can choose:

  • g(x)=x+4g(x) = x + 4
  • f(x)=x2+2xf(x) = x^2 + 2x

This gives: f(g(x))=f(x+4)=(x+4)2+2(x+4)=h(x)f(g(x)) = f(x + 4) = (x + 4)^2 + 2(x + 4) = h(x)

72. h(x)=(x+3)3/2+4(x+3)1/2h(x) = (x + 3)^{3/2} + 4(x + 3)^{1/2}

We can choose:

  • g(x)=x+3g(x) = x + 3
  • f(x)=x3/2+4x1/2f(x) = x^{3/2} + 4x^{1/2}

This gives: f(g(x))=f(x+3)=(x+3)3/2+4(x+3)1/2=h(x)f(g(x)) = f(x + 3) = (x + 3)^{3/2} + 4(x + 3)^{1/2} = h(x)


Would you like any further details on these problems?

Here are 5 related questions for further practice:

  1. How do you determine the functions ff and gg in function composition problems?
  2. Can you find alternative pairs of ff and gg for each h(x)h(x)?
  3. What happens if you reverse ff and gg? Does gfg \circ f work for these problems?
  4. How do the domains of ff, gg, and hh affect the choice of functions?
  5. Can you write the composition of three functions to represent more complex h(x)h(x)?

Tip: When solving composition problems, focus on identifying the "inner" and "outer" parts of the function to split into g(x)g(x) and f(x)f(x) respectively.

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Math Problem Analysis

Mathematical Concepts

Function Composition
Algebra
Radicals
Quadratics

Formulas

(f ◦ g)(x) = f(g(x))
Basic algebraic manipulations
Square roots and cube roots

Theorems

Properties of composite functions
Radical simplification
Powers of binomials

Suitable Grade Level

Grades 10-12