Math Problem Statement

The table contains some input-output info for the functions f and g. The value of (g∘f)(1) = -1. The functions f(x) = 3x + 4 and g(x) = (x - 4)/3 are inverse of each other. If f(x) = x² - 2x and g(x) = x² + 1, then Dg∘f is (-∞, ∞).

Solution

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Question 7

The problem asks for the value of (gf)(1)(g \circ f)(1), where (gf)(x)=g(f(x))(g \circ f)(x) = g(f(x)).

Given:

  • f(1)=1f(1) = -1
  • g(1)=4g(-1) = 4

We calculate:

  1. First, find f(1)f(1): f(1)=1f(1) = -1.
  2. Then, substitute this into g(x)g(x): g(1)=4g(-1) = 4.

So, (gf)(1)=g(f(1))=g(1)=4(g \circ f)(1) = g(f(1)) = g(-1) = 4.

The statement says that the value is 1-1, but we found it to be 44, so the correct answer is False.

Question 8

The problem asks whether the functions f(x)=3x+4f(x) = 3x + 4 and g(x)=x43g(x) = \frac{x - 4}{3} are inverses of each other.

To verify, compose the two functions (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x):

  1. f(g(x))f(g(x)): f(g(x))=f(x43)=3(x43)+4=x4+4=xf(g(x)) = f\left(\frac{x - 4}{3}\right) = 3\left(\frac{x - 4}{3}\right) + 4 = x - 4 + 4 = x

  2. g(f(x))g(f(x)): g(f(x))=g(3x+4)=3x+443=3x3=xg(f(x)) = g(3x + 4) = \frac{3x + 4 - 4}{3} = \frac{3x}{3} = x

Since both compositions (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x) equal xx, the functions are indeed inverses. So, the correct answer is True.

Question 9

The problem asks for the domain of the composition DgfD_{g \circ f} where:

  • f(x)=x22xf(x) = x^2 - 2x
  • g(x)=x2+1g(x) = x^2 + 1

The domain of the composition g(f(x))g(f(x)) is determined by the domain of f(x)f(x) and the range of f(x)f(x).

  1. The domain of f(x)f(x), which is a quadratic function, is all real numbers (,)(-\infty, \infty).
  2. The range of f(x)f(x) is also all real numbers because it's a quadratic function, which opens upwards, with the minimum at f(1)=1f(1) = -1.

Since g(x)=x2+1g(x) = x^2 + 1 also has a domain of all real numbers (,)(-\infty, \infty), and since g(x)g(x) is defined for all f(x)f(x), the domain DgfD_{g \circ f} will also be all real numbers.

Thus, the correct answer is True.

Would you like to go into more details or ask any further questions?

Here are some relative questions:

  1. What is the significance of the composition of functions in mathematics?
  2. Can you explain how to find the inverse of a function?
  3. What are the properties of quadratic functions that determine their domain and range?
  4. How do you determine if a given function is injective (one-to-one)?
  5. How does the domain and range of a function affect the composition of two functions?

Tip: Always check both the domain and range when dealing with function compositions, as they directly affect the possible inputs and outputs.

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Math Problem Analysis

Mathematical Concepts

Function Composition
Inverse Functions
Quadratic Functions
Domains of Functions

Formulas

(g∘f)(x) = g(f(x))
Inverse function verification: f(g(x)) = x and g(f(x)) = x
Domain of composition: Dg∘f

Theorems

Function Composition Theorem
Inverse Function Theorem

Suitable Grade Level

Grades 9-12