The question in the image asks to find $f(g(x))$, where:

• $f(x) = 3x - 5$
• $g(x) = 2x - 1$

To find $f(g(x))$, we substitute $g(x)$ into $f(x)$.

Step-by-Step Solution:

1. $f(g(x)) = f(2x - 1)$

   Since $f(x) = 3x - 5$, replace $x$ in $f(x)$ with $g(x) = 2x - 1$:

2. $f(g(x)) = 3(2x - 1) - 5$

3. Simplify:

   $f(g(x)) = 6x - 3 - 5$ $f(g(x)) = 6x - 8$

Thus, $f(g(x)) = 6x - 8$.

Would you like further clarification, or any additional details on this solution? Here are some related questions:

1. What is the process to find $g(f(x))$?
2. How does composition of functions work generally?
3. Can you explain how domain and range are affected by function composition?
4. How would you invert $f(x)$ or $g(x)$ from this problem?
5. What would happen if $g(x)$ was a quadratic function instead?

Tip: In function composition, always substitute the inner function into the outer function carefully, and simplify step by step!