Math Problem Statement

Find

left parenthesis f circle g right parenthesis left parenthesis x right parenthesis(f◦g)(x)

and

left parenthesis g circle f right parenthesis left parenthesis x right parenthesis(g◦f)(x)

and the domain of each.

​f(x)equals=xplus+11​,

​g(x)equals=3 x squared minus 2 x minus 13x2−2x−1

Question content area bottom

Part 1

left parenthesis f circle g right parenthesis left parenthesis x right parenthesis(f◦g)(x)equals=enter your response here

​(Simplify your​ answer.)

Solution

To find (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x), we will start by defining each function and then proceed with their compositions.

Step 1: Define the Functions

Given:

  • f(x)=x+11f(x) = x + 11
  • g(x)=3x22x1g(x) = 3x^2 - 2x - 1

Part 1: Find (fg)(x)(f \circ g)(x)

The composition (fg)(x)(f \circ g)(x) is defined as f(g(x))f(g(x)), meaning we will substitute g(x)g(x) into f(x)f(x).

  1. Substitute g(x)=3x22x1g(x) = 3x^2 - 2x - 1 into f(x)f(x): f(g(x))=f(3x22x1)f(g(x)) = f(3x^2 - 2x - 1)
  2. Since f(x)=x+11f(x) = x + 11, replace xx with 3x22x13x^2 - 2x - 1: f(g(x))=(3x22x1)+11f(g(x)) = (3x^2 - 2x - 1) + 11
  3. Simplify the expression: f(g(x))=3x22x1+11f(g(x)) = 3x^2 - 2x - 1 + 11 f(g(x))=3x22x+10f(g(x)) = 3x^2 - 2x + 10

So, (fg)(x)=3x22x+10(f \circ g)(x) = 3x^2 - 2x + 10.

Part 2: Find (gf)(x)(g \circ f)(x)

The composition (gf)(x)(g \circ f)(x) is defined as g(f(x))g(f(x)), meaning we will substitute f(x)f(x) into g(x)g(x).

  1. Substitute f(x)=x+11f(x) = x + 11 into g(x)g(x): g(f(x))=g(x+11)g(f(x)) = g(x + 11)
  2. Since g(x)=3x22x1g(x) = 3x^2 - 2x - 1, replace xx with x+11x + 11: g(f(x))=3(x+11)22(x+11)1g(f(x)) = 3(x + 11)^2 - 2(x + 11) - 1
  3. Expand (x+11)2(x + 11)^2: (x+11)2=x2+22x+121(x + 11)^2 = x^2 + 22x + 121
  4. Substitute back: g(f(x))=3(x2+22x+121)2(x+11)1g(f(x)) = 3(x^2 + 22x + 121) - 2(x + 11) - 1
  5. Distribute and simplify each term: =3x2+66x+3632x221= 3x^2 + 66x + 363 - 2x - 22 - 1 =3x2+64x+340= 3x^2 + 64x + 340

So, (gf)(x)=3x2+64x+340(g \circ f)(x) = 3x^2 + 64x + 340.

Part 3: Determine the Domains

  • Domain of f(x)=x+11f(x) = x + 11: All real numbers, since it’s a linear function.
  • Domain of g(x)=3x22x1g(x) = 3x^2 - 2x - 1: All real numbers, since it’s a polynomial.

Since both f(x)f(x) and g(x)g(x) are defined for all real numbers, their compositions (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x) are also defined for all real numbers.

Final Answer

  1. (fg)(x)=3x22x+10(f \circ g)(x) = 3x^2 - 2x + 10, with domain: all real numbers.
  2. (gf)(x)=3x2+64x+340(g \circ f)(x) = 3x^2 + 64x + 340, with domain: all real numbers.

Would you like further clarification on any of these steps?


Related Questions to Explore

  1. What are other properties of function compositions?
  2. How does changing f(x)f(x) or g(x)g(x) affect (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x)?
  3. How would the domains change if f(x)f(x) or g(x)g(x) had restricted domains?
  4. Can the composition of functions be commutative? Why or why not?
  5. What is the range of (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x)?

Tip

Always start by carefully identifying each function before substituting; this ensures clarity and prevents errors.

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Math Problem Analysis

Mathematical Concepts

Function Composition
Domains of Functions
Polynomial Functions

Formulas

(f◦g)(x) = f(g(x))
(g◦f)(x) = g(f(x))

Theorems

Composition of Functions

Suitable Grade Level

Grades 10-12