Consider the following functions.

f={(−4,−1),(−3,−1),(−2,−3),(3,0)}

and

g={(5,3),(4,−1),(−2,−4),(−4,−5)}
Step 1 of 4: Find (f+g)(−2).

We are asked to find \((f+g)(-2)\), which involves adding the values of the functions \(f\) and \(g\) at \(x = -2\). Here's the process step by step:

### Step 1: Identify \(f(-2)\) and \(g(-2)\)

From the set of ordered pairs for \(f\):
- \(f = \{(-4, -1), (-3, -1), (-2, -3), (3, 0)\}\)
- The pair for \(x = -2\) is \((-2, -3)\), so \(f(-2) = -3\).

From the set of ordered pairs for \(g\):
- \(g = \{(5, 3), (4, -1), (-2, -4), (-4, -5)\}\)
- The pair for \(x = -2\) is \((-2, -4)\), so \(g(-2) = -4\).

### Step 2: Add \(f(-2)\) and \(g(-2)\)

Now, we add the two values:
\[
f(-2) + g(-2) = -3 + (-4) = -7
\]

### Conclusion:
\[
(f+g)(-2) = -7
\]

Would you like further details or have any questions about this process? Here are 5 related questions you might find helpful:

1. How do you find \( (f - g)(-2) \)?
2. What are the domain and range of function \(f\)?
3. Can \( f(x) + g(x) \) result in complex values?
4. How would you represent \(f+g\) as a new function?
5. What would change if the functions had more ordered pairs?

**Tip:** Always check both functions for the same input value before performing any operations like addition or subtraction.

Consider the following functions.

f = {(-4, -1), (-3, -1), (-2, -3), (3, 0)}

g = {(5, 3), (4, -1), (-2, -4), (-4, -5)}

Step 1 of 4: Find (f+g)(-2).

Learn how to find the value of (f+g)(-2) using two sets of functions. This problem explores ordered pairs, function addition, and step-by-step operations. Suitable for students in Grades 8-10.

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