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The given problem asks to evaluate the function \( (f + g)(-6) \) where the functions are:

\[
f(x) = x + 3 \quad \text{and} \quad g(x) = x^2 - 2.
\]

To find \( (f + g)(-6) \), we first need to add the two functions \( f(x) \) and \( g(x) \), then substitute \( x = -6 \) into the resulting function.

### Step 1: Adding \( f(x) \) and \( g(x) \)
\[
(f + g)(x) = f(x) + g(x) = (x + 3) + (x^2 - 2) = x^2 + x + 1.
\]

### Step 2: Substituting \( x = -6 \) into \( f + g \)
\[
(f + g)(-6) = (-6)^2 + (-6) + 1 = 36 - 6 + 1 = 31.
\]

Thus, \( (f + g)(-6) = 31 \).

Would you like further clarification or more details? Here are five related questions you might find interesting:

1. How do you find the value of \( f(-6) \) and \( g(-6) \) separately?
2. Can you evaluate \( (f \cdot g)(-6) \)?
3. How would you graph \( f(x) \) and \( g(x) \) on the same plane?
4. How does adding functions differ from composing functions \( (f \circ g)(x) \)?
5. What happens if you subtract the functions \( f(x) - g(x) \) and evaluate at \( x = -6 \)?

**Tip:** Always simplify functions first before substituting values to avoid calculation errors.

Evaluate the function for f(x) = x + 3 and g(x) = x^2 - 2. Find (f + g)(-6).

Learn how to evaluate the sum of two functions f(x) = x + 3 and g(x) = x^2 - 2 at x = -6. This problem involves adding functions and substituting values. Suitable for students in Grades 7-9.

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