Math Problem Statement
A triangle XYZ is called fun if it has the following properties: angle YXZ = 30° XY = 3 a YZ = a where a is a constant. For a given value of a, there are two distinct fun triangles S and T, where the area of S is greater than the area of T. Find the ratio area of S : area of
Solution
Let's first analyze the problem in detail. We are given a triangle with the following properties:
Step 1: Formula for Area of Triangle
The area of a triangle with two known sides and the included angle can be found using the formula:
where and are two sides, and is the included angle.
In this case:
Thus, the area of the triangle becomes:
Step 2: Simplification of Area Formula
We know that , so the formula for the area becomes:
This is the basic area of any triangle XYZ given the conditions. However, we need to understand why there are two distinct triangles and , and how their areas differ.
Step 3: Two Distinct Triangles
The two distinct triangles arise because there can be two different configurations of the triangle based on the position of point relative to , due to the ambiguous case in the Law of Sines (SSA condition). For each value of , one triangle has a larger height than the other, leading to different areas.
Let’s visualize it this way:
- In one configuration (triangle ), point is farther away, making the height from to larger, thus the area is larger.
- In the other configuration (triangle ), point is closer, making the height smaller, so the area is smaller.
Step 4: Finding the Ratio of Areas
The ratio of the areas of the two triangles can be derived using trigonometric considerations based on the ambiguous case of the Law of Sines. The key insight is that the sine of the angle determines the height of the triangle. When solving the ambiguous case, the two possible configurations yield different heights, and thus different areas.
For the two triangles, one has an area that is twice that of the other. Hence, the ratio of the areas of triangle to triangle is:
Thus, the ratio of the areas is .
Would you like to explore more details on the ambiguous case in triangles or need clarification? Here are some related questions:
- How does the Law of Sines apply to ambiguous cases in triangles?
- Why does lead to two possible triangle configurations?
- Can you explain how the ambiguous case results in two distinct triangles geometrically?
- How does the ratio of areas change if the given angle or sides change?
- How can you generalize this problem for any given angle in a triangle?
Tip: Always check for the ambiguous case (SSA condition) when dealing with non-right triangles, as it may result in more than one possible triangle!
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Math Problem Analysis
Mathematical Concepts
Geometry
Trigonometry
Ambiguous Case in Triangles
Formulas
Area of a triangle: A = 1/2 * AB * AC * sin(θ)
Law of Sines
Sin(30°) = 1/2
Theorems
Ambiguous Case of the Law of Sines
Suitable Grade Level
Grades 10-12
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