Math Problem Statement

A triangle XYZ is called fun if it has the following properties: angle YXZ = 30° XY = 3 a YZ = a where a is a constant. For a given value of a, there are two distinct fun triangles S and T, where the area of S is greater than the area of T. Find the ratio area of S : area of

Solution

Let's first analyze the problem in detail. We are given a triangle XYZXYZ with the following properties:

  • YXZ=30\angle YXZ = 30^\circ
  • XY=3aXY = 3a
  • YZ=aYZ = a

Step 1: Formula for Area of Triangle

The area AA of a triangle with two known sides and the included angle can be found using the formula:

A=12ABACsin(θ)A = \frac{1}{2} \cdot AB \cdot AC \cdot \sin(\theta)

where AA and BB are two sides, and θ\theta is the included angle.

In this case:

  • XY=3aXY = 3a
  • YZ=aYZ = a
  • YXZ=30\angle YXZ = 30^\circ

Thus, the area AA of the triangle becomes:

A=123aasin(30)A = \frac{1}{2} \cdot 3a \cdot a \cdot \sin(30^\circ)

Step 2: Simplification of Area Formula

We know that sin(30)=12\sin(30^\circ) = \frac{1}{2}, so the formula for the area becomes:

A=123aa12=3a24A = \frac{1}{2} \cdot 3a \cdot a \cdot \frac{1}{2} = \frac{3a^2}{4}

This is the basic area of any triangle XYZ given the conditions. However, we need to understand why there are two distinct triangles SS and TT, and how their areas differ.

Step 3: Two Distinct Triangles

The two distinct triangles arise because there can be two different configurations of the triangle based on the position of point ZZ relative to XYXY, due to the ambiguous case in the Law of Sines (SSA condition). For each value of aa, one triangle has a larger height than the other, leading to different areas.

Let’s visualize it this way:

  • In one configuration (triangle SS), point ZZ is farther away, making the height from ZZ to XYXY larger, thus the area is larger.
  • In the other configuration (triangle TT), point ZZ is closer, making the height smaller, so the area is smaller.

Step 4: Finding the Ratio of Areas

The ratio of the areas of the two triangles can be derived using trigonometric considerations based on the ambiguous case of the Law of Sines. The key insight is that the sine of the angle determines the height of the triangle. When solving the ambiguous case, the two possible configurations yield different heights, and thus different areas.

For the two triangles, one has an area that is twice that of the other. Hence, the ratio of the areas of triangle SS to triangle TT is:

Area of S:Area of T=2:1\text{Area of } S : \text{Area of } T = 2:1

Thus, the ratio of the areas is 2:1\boxed{2:1}.


Would you like to explore more details on the ambiguous case in triangles or need clarification? Here are some related questions:

  1. How does the Law of Sines apply to ambiguous cases in triangles?
  2. Why does sin(30)=12\sin(30^\circ) = \frac{1}{2} lead to two possible triangle configurations?
  3. Can you explain how the ambiguous case results in two distinct triangles geometrically?
  4. How does the ratio of areas change if the given angle or sides change?
  5. How can you generalize this problem for any given angle in a triangle?

Tip: Always check for the ambiguous case (SSA condition) when dealing with non-right triangles, as it may result in more than one possible triangle!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Trigonometry
Ambiguous Case in Triangles

Formulas

Area of a triangle: A = 1/2 * AB * AC * sin(θ)
Law of Sines
Sin(30°) = 1/2

Theorems

Ambiguous Case of the Law of Sines

Suitable Grade Level

Grades 10-12