To solve for the magnitude of the frictional force or the coefficient of friction, I need to clarify a few details, as the question is a bit unclear.

Typically, in friction problems, the formula used is:

$f_{\text{friction}} = \mu \cdot N$

Where:

• $f_{\text{friction}}$ is the frictional force,
• $\mu$ is the coefficient of friction, and
• $N$ is the normal force (the force perpendicular to the surface, usually the weight of the object).

Based on your question, there are two numbers given:

1. 1.0 (Could be the coefficient of friction $\mu$?)
2. 3N (Could be the frictional force $f_{\text{friction}}$?)

If the given values are:

• $\mu = 1.0$ (coefficient of friction),
• $f_{\text{friction}} = 3N$ (frictional force),

Then, you can calculate the normal force $N$ using the equation:

$f_{\text{friction}} = \mu \cdot N$

Substituting the values:

$3 = 1.0 \cdot N$

This gives:

$N = 3 \, \text{N}$

So the normal force is 3N.

Alternatively, if you are looking for the coefficient of friction, the same formula applies, but you'd rearrange it:

$\mu = \frac{f_{\text{friction}}}{N}$

If you provide the normal force (N), you can calculate the coefficient of friction $\mu$.

Would you like to clarify the problem further, or is there additional information I can assist with?