Math Problem Statement

The friction force affecting the body in the opposite figure is

5 N

10 N

20 N

40 N

The friction force affecting the body in the opposite figure is: 5 N 10 N 20 N 40 N

Solution

To solve this problem, we need to determine the frictional force acting on the object based on the given information. Let's break it down step-by-step:

Information given:

  1. Mass of the block (mm) = 4 kg
  2. Applied force (FF) = 50 N
  3. Acceleration (aa) = 10 m/s²
  4. Frictional force opposes the motion.

Step 1: Calculate the net force (FnetF_{\text{net}}) acting on the object.

Using Newton's second law of motion:
Fnet=maF_{\text{net}} = m \cdot a Substituting the given values: Fnet=410=40NF_{\text{net}} = 4 \cdot 10 = 40 \, \text{N}

Step 2: Relating the forces.

The net force is the result of the applied force minus the frictional force: Fnet=FFfrictionF_{\text{net}} = F - F_{\text{friction}} Rearranging to find the frictional force: Ffriction=FFnetF_{\text{friction}} = F - F_{\text{net}}

Substitute the values: Ffriction=5040=10NF_{\text{friction}} = 50 - 40 = 10 \, \text{N}

Final Answer:

The frictional force is 10 N.


Let me know if you want further clarification! 😊

Related Questions:

  1. What is the significance of frictional force in motion problems?
  2. How does Newton's second law help in analyzing forces?
  3. What happens if there is no friction in the given scenario?
  4. How would the result change if the applied force increased to 60 N?
  5. Can frictional force ever exceed the applied force? Why or why not?

Tip:

Always break down force problems into components using a free-body diagram to identify all acting forces clearly!

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Math Problem Analysis

Mathematical Concepts

Newton's Second Law of Motion
Frictional Forces
Net Force

Formulas

Newton's Second Law: F_net = m * a
Frictional Force: F_friction = F_applied - F_net

Theorems

Newton's Second Law of Motion

Suitable Grade Level

Grades 9-11