Math Problem Statement

there were some participants at a race. 1 / 5 of the prticipants were adults while the rest were children. 4 / 7 of the adults were men and there were 5 1 boys. after all the men and boys left, there were 2 / 5 of the participants remaining at the race. what fraction of the total participants was men? ho many participants were there all together?

Solution

Let's break down the problem step by step.

Step 1: Defining Variables

Let PP represent the total number of participants in the race.

  • 15\frac{1}{5} of the participants were adults, so the number of adults is 15P\frac{1}{5}P.
  • The remaining participants were children, so the number of children is P15P=45PP - \frac{1}{5}P = \frac{4}{5}P.
  • 47\frac{4}{7} of the adults were men. Therefore, the number of men is 47×15P=435P\frac{4}{7} \times \frac{1}{5}P = \frac{4}{35}P.
  • We are told there are 51 boys, so the number of boys is 51.

Step 2: Analyzing Remaining Participants

  • After all the men and boys left, 25\frac{2}{5} of the participants remained. This means 35\frac{3}{5} of the participants left the race.
  • The participants who left were all the men and boys. So, the number of people who left is the sum of the number of men and boys, i.e., 435P+51\frac{4}{35}P + 51.
  • Since 35\frac{3}{5} of the total participants left, we have the equation: 35P=435P+51\frac{3}{5}P = \frac{4}{35}P + 51

Step 3: Solving the Equation

Let's solve for PP:

  1. Multiply both sides by 35 to eliminate the fractions: 35×35P=35×(435P+51)35 \times \frac{3}{5}P = 35 \times \left( \frac{4}{35}P + 51 \right) Simplifying both sides: 21P=4P+178521P = 4P + 1785
  2. Subtract 4P4P from both sides: 17P=178517P = 1785
  3. Divide both sides by 17: P=178517=105P = \frac{1785}{17} = 105

So, there were 105 participants in total.

Step 4: Fraction of Participants that were Men

  • We already know that the number of men is 435P\frac{4}{35}P.
  • Substituting P=105P = 105 into this: Number of men=435×105=12\text{Number of men} = \frac{4}{35} \times 105 = 12 Thus, the fraction of the total participants that were men is: 12105=435\frac{12}{105} = \frac{4}{35}

Final Answers:

  1. The fraction of the total participants that were men is 435\frac{4}{35}.
  2. The total number of participants was 105.

Would you like more details on any part of the solution?

Here are 5 related questions to extend this topic:

  1. What fraction of the participants were boys?
  2. How many children were there in total?
  3. What fraction of the participants were women?
  4. How many women participated in the race?
  5. How many girls were there among the participants?

Tip: When solving word problems, defining variables early can help clarify complex relationships and make equations easier to set up.

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Math Problem Analysis

Mathematical Concepts

Algebra
Fractions
Word Problems

Formulas

Number of adults = 1/5 * P
Number of children = 4/5 * P
Number of men = 4/7 * (1/5 * P)
Equation: (3/5 * P) = (4/35 * P) + 51

Theorems

Fraction Multiplication
Linear Equations

Suitable Grade Level

Grades 8-10