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To solve this problem, let's break it down step-by-step.

1. Let the total number of pupils in the class be \( T \).
2. We know that:
   - \(\frac{5}{12}\) of the pupils in the class are girls.
   - Therefore, the fraction of boys in the class is \(1 - \frac{5}{12} = \frac{7}{12}\).

3. The problem states that:
   - \(\frac{2}{7}\) of the boys are scouts.
   - None of the girls are scouts.

4. Now, we calculate the fraction of the pupils who are scouts.

   Since only boys are scouts, we need to find the fraction of the total class that these scouts represent:
   - The number of boys is \(\frac{7}{12} \times T\).
   - Of these boys, \(\frac{2}{7}\) are scouts.

5. So, the number of scouts is:
   \[
   \frac{2}{7} \times \frac{7}{12} \times T = \frac{2}{12} \times T = \frac{1}{6} \times T
   \]

6. Therefore, \(\frac{1}{6}\) of the pupils in the class are scouts.

### Answer:
The fraction of the pupils in the class who are scouts is \(\frac{1}{6}\).

Would you like further details or have any questions?

Here are five related questions for further practice:
1. What fraction of the class are boys?
2. If there are 60 pupils in the class, how many of them are scouts?
3. What fraction of the class are not scouts?
4. If \(\frac{3}{7}\) of the boys were scouts instead of \(\frac{2}{7}\), what would be the fraction of scouts in the class?
5. How would the fraction change if \(\frac{3}{12}\) of the pupils in the class were girls instead?

**Tip:** When dealing with fractions of a group, multiply the fractions step-by-step to avoid errors.

5/12 of the pupils in a class are girls. 2/7 of the boys and none of the girls in the class are scouts. What fraction of the pupils in the class are scouts?

Solve a math problem involving fractions and proportions. Given that 5/12 of the pupils are girls, and 2/7 of the boys are scouts, find the fraction of the entire class that is scouts. This problem is suitable for students in Grades 6-8.

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