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The problem asks how many toys are left to be built if Harry and Matthew have 56 toys in total, Harry builds \( \frac{3}{4} \) of the toys, and Matthew builds \( \frac{1}{7} \) of the toys.

Let's break this down:

1. **Total toys**: 56
2. **Harry's contribution**: \( \frac{3}{4} \) of the toys
   \[
   \frac{3}{4} \times 56 = 42 \text{ toys}
   \]
3. **Matthew's contribution**: \( \frac{1}{7} \) of the toys
   \[
   \frac{1}{7} \times 56 = 8 \text{ toys}
   \]
4. **Total built by Harry and Matthew**: \( 42 + 8 = 50 \) toys
5. **Toys left to be built**: 
   \[
   56 - 50 = 6 \text{ toys}
   \]

Thus, **6 toys** are left to be built.

Do you need further details, or any additional questions?

Here are 5 related questions:
1. What fraction of the toys is left to be built?
2. If Harry built \( \frac{1}{2} \) of the toys instead of \( \frac{3}{4} \), how many would be left?
3. How many toys would be left if Matthew built \( \frac{1}{5} \) of the toys instead of \( \frac{1}{7} \)?
4. If there were 100 toys to build, how many would be left after Harry and Matthew completed their parts?
5. What percentage of the total toys did Harry and Matthew complete together?

**Tip**: Always confirm fractions are based on the same total when combining or comparing them.

Harry and Matthew have 56 toys to build. Harry builds 3/4 of the toys, while Matthew builds 1/7 of the toys. How many toys are left to be built?

Solve a real-world problem involving fractions: Harry and Matthew have 56 toys to build. Harry builds 3/4 of the toys, while Matthew builds 1/7. Find out how many toys are left to be built after their contributions, using basic arithmetic and fraction operations. Suitable for students in Grades 5-7.

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