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The question reads: 

**"One-third of the students at Finley High School are in a club. Two-fifths of the students in a club are in theater. What fraction of the students who are in a club are in theater? Explain your answer."**

### Solution:

We are asked to find the fraction of students who are in a club and also in theater. 

1. **Step 1: Fraction of students in a club**  
   The problem states that **one-third** (or \(\frac{1}{3}\)) of the students are in a club.

2. **Step 2: Fraction of students in theater**  
   Out of those students in a club, **two-fifths** (or \(\frac{2}{5}\)) are in theater.

3. **Step 3: Find the fraction of the total students who are both in a club and in theater**  
   To find the fraction of all students who are in theater, we multiply the two fractions:

   \[
   \frac{1}{3} \times \frac{2}{5} = \frac{2}{15}
   \]

### Final Answer:
The fraction of all students at Finley High School who are both in a club and in theater is \(\frac{2}{15}\).

Would you like a more detailed breakdown of these steps?

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Here are five related questions you might explore:
1. What fraction of students are in clubs but not in theater?
2. How many students are in theater if the total number of students is 150?
3. What would the fraction be if half of the students in clubs were in theater instead?
4. Can you express the result as a decimal or percentage?
5. How would the fractions change if three-fifths of students in clubs were in theater?

**Tip**: When multiplying fractions, always simplify the fractions before multiplying, if possible.

One-third of the students at Finley High School are in a club. Two-fifths of the students in a club are in theater. What fraction of the students who are in a club are in theater? Explain your answer.

Learn how to find the fraction of students in theater out of those who are in a club at Finley High School. Using fraction multiplication, this problem illustrates basic concepts in fractions. Suitable for Grades 5-7.

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