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The problem shown in the image seems to involve dividing a mixed fraction of pounds of pasta by a fraction to determine how many casserole dishes can be made and how much pasta will remain.

The restaurant has **3 and 3/5 pounds** of pasta, and they need to figure out how many casseroles can be made with this amount. Each casserole uses **5/7 pounds** of pasta.

Here’s how to solve the problem step by step:

1. **Convert the mixed number to an improper fraction**:
   \[
   3 \frac{3}{5} = \frac{18}{5}
   \]
   
2. **Divide the total amount of pasta by the amount needed for one casserole**:
   \[
   \frac{18}{5} \div \frac{5}{7}
   \]
   Dividing by a fraction is the same as multiplying by its reciprocal:
   \[
   \frac{18}{5} \times \frac{7}{5} = \frac{18 \times 7}{5 \times 5} = \frac{126}{25}
   \]
   
3. **Convert the improper fraction to a mixed number**:
   \[
   \frac{126}{25} = 5 \frac{1}{25}
   \]
   So, the restaurant can make **5 full casseroles** with **1/25 pound** of pasta left over.

Thus, the restaurant can make **5 casseroles** with **1/25 pounds of pasta left over**.

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Would you like any more details on this solution, or any clarifications? 

Here are some related questions to consider:
1. How would the solution change if the restaurant had a different amount of pasta?
2. What if each casserole used a different fraction of pasta, like 3/4 pounds?
3. Can you think of a real-life scenario where you might need to solve a problem similar to this one?
4. How do you convert an improper fraction to a mixed number?
5. What is the importance of reciprocals when dividing fractions?

**Tip**: Always remember to check if a fraction can be simplified before converting it into a mixed number!

A restaurant has 3 3/5 pounds of pasta to make casserole dishes. Each casserole uses 5/7 pounds of pasta. How many casseroles can be made, and how much pasta will remain?

This problem involves dividing a mixed fraction to determine how many casserole dishes can be made from 3 3/5 pounds of pasta, where each casserole uses 5/7 pounds. Learn to solve using improper fractions and multiplication of reciprocals, suitable for Grade 6 students.

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