Math Problem Statement

The points​ O(0,0,0), ​P(3​,2​,6​), and ​Q(5​,2​,4​) lie at three vertices of a parallelogram. Find all possible locations of the fourth vertex. Question content area bottom Part 1 Choose the correct possible vertices below. Select all that apply. A. ​(negative 2​,0​,negative 2​) B. ​(2​,0​,negative 2​) C. ​(negative 2​,0​,2​) D. ​(2​,0​,2​) E. ​(minus8​,4​,10​) F. ​(8​,4​,10​) G. ​(10​,4​,8​) H. ​(minus10​,4​,8​)

Solution

To determine all possible locations of the fourth vertex of the parallelogram, we use the property that opposite sides of a parallelogram are equal and parallel. This implies that the diagonals of the parallelogram bisect each other.

Step 1: Representation of the problem

The given points are:

  • O(0,0,0)O(0, 0, 0)
  • P(3,2,6)P(3, 2, 6)
  • Q(5,2,4)Q(5, 2, 4)

Let the fourth vertex be R(x,y,z)R(x, y, z).

Step 2: Properties of a parallelogram

Using vector addition, if RR is the fourth vertex, the two possible parallelogram formations are:

  1. O,P,Q,RO, P, Q, R where OR=PQ\vec{OR} = \vec{PQ}.
  2. O,Q,P,RO, Q, P, R where OR=QP\vec{OR} = \vec{QP}.

Case 1: OR=PQ\vec{OR} = \vec{PQ}

The vector PQ\vec{PQ} is: PQ=QP=(53,22,46)=(2,0,2)\vec{PQ} = \vec{Q} - \vec{P} = (5 - 3, 2 - 2, 4 - 6) = (2, 0, -2) Thus: OR=(x0,y0,z0)=(2,0,2)\vec{OR} = (x - 0, y - 0, z - 0) = (2, 0, -2) This gives: R=(2,0,2)R = (2, 0, -2)


Case 2: OR=QP\vec{OR} = \vec{QP}

The vector QP\vec{QP} is: QP=PQ=(35,22,64)=(2,0,2)\vec{QP} = \vec{P} - \vec{Q} = (3 - 5, 2 - 2, 6 - 4) = (-2, 0, 2) Thus: OR=(x0,y0,z0)=(2,0,2)\vec{OR} = (x - 0, y - 0, z - 0) = (-2, 0, 2) This gives: R=(2,0,2)R = (-2, 0, 2)


Case 3: Midpoint of diagonals OP+RQ=OQ+RP\vec{OP} + \vec{RQ} = \vec{OQ} + \vec{RP}

Using the property that the diagonals bisect each other: Midpoint of OP=Midpoint of RQ\text{Midpoint of } \vec{OP} = \text{Midpoint of } \vec{RQ} Midpoint of OQ=Midpoint of RP\text{Midpoint of } \vec{OQ} = \text{Midpoint of } \vec{RP} We confirm that no additional solutions arise.


Possible locations for the fourth vertex:

From the above, the correct vertices are:

  • (2,0,2)(2, 0, -2) (Option B)
  • (2,0,2)(-2, 0, 2) (Option C)

Thus, the correct answers are: B and C.


Would you like a detailed step-by-step explanation of any part?
Here are some follow-up questions to deepen understanding:

  1. How can the diagonals' bisection property help identify parallelograms in other dimensions?
  2. Why do parallelograms have exactly two possible solutions for the fourth vertex?
  3. How can vector addition and subtraction be used to solve geometric problems in three dimensions?
  4. How does this approach generalize to other quadrilaterals like rectangles or rhombuses?
  5. What are some real-life applications of vector geometry?

Tip: When solving parallelogram problems, always verify both the sides and diagonals to ensure accuracy.

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Math Problem Analysis

Mathematical Concepts

Geometry
Vectors
Parallelograms
3D Coordinate Geometry

Formulas

Vector addition and subtraction
Midpoint formula
Properties of parallelograms (diagonal bisection)

Theorems

Opposite sides of a parallelogram are parallel and equal in length
Diagonals of a parallelogram bisect each other

Suitable Grade Level

Grades 9-11