Math Problem Statement

What are the fourth roots of i?

Solution

The image contains the handwritten phrase: "The fourth roots of ii = ±1, ±i."

This statement refers to finding the fourth roots of the complex number ii, where ii is the imaginary unit, defined as i2=1i^2 = -1.

Solving for the Fourth Roots of ii:

The fourth roots of a complex number can be found using polar coordinates and De Moivre's Theorem. Let’s break it down:

  1. Express ii in polar form:

    • i=0+1ii = 0 + 1i, which in polar form is: r=1(magnitude),θ=π2(angle, or argument)r = 1 \quad \text{(magnitude)}, \quad \theta = \frac{\pi}{2} \quad \text{(angle, or argument)} Hence, i=cis(π2)i = \text{cis}\left( \frac{\pi}{2} \right), where cis(θ)\text{cis}(\theta) is shorthand for cos(θ)+isin(θ)\cos(\theta) + i \sin(\theta).
  2. Apply De Moivre's Theorem:

    • To find the fourth roots, we need to solve z4=iz^4 = i. According to De Moivre’s Theorem: zk=r4cis(θ+2kπ4),k=0,1,2,3z_k = \sqrt[4]{r} \cdot \text{cis}\left( \frac{\theta + 2k\pi}{4} \right), \quad k = 0, 1, 2, 3 Since r=1r = 1, r4=1\sqrt[4]{r} = 1, and θ=π2\theta = \frac{\pi}{2}, we get: zk=cis(π2+2kπ4)z_k = \text{cis} \left( \frac{\frac{\pi}{2} + 2k\pi}{4} \right)
  3. Find the four distinct roots (for k=0,1,2,3k = 0, 1, 2, 3):

    • For k=0k = 0: z0=cis(π8)=cos(π8)+isin(π8)z_0 = \text{cis} \left( \frac{\pi}{8} \right) = \cos\left( \frac{\pi}{8} \right) + i\sin\left( \frac{\pi}{8} \right)
    • For k=1k = 1: z1=cis(5π8)=cos(5π8)+isin(5π8)z_1 = \text{cis} \left( \frac{5\pi}{8} \right) = \cos\left( \frac{5\pi}{8} \right) + i\sin\left( \frac{5\pi}{8} \right)
    • For k=2k = 2: z2=cis(9π8)=cos(9π8)+isin(9π8)z_2 = \text{cis} \left( \frac{9\pi}{8} \right) = \cos\left( \frac{9\pi}{8} \right) + i\sin\left( \frac{9\pi}{8} \right)
    • For k=3k = 3: z3=cis(13π8)=cos(13π8)+isin(13π8)z_3 = \text{cis} \left( \frac{13\pi}{8} \right) = \cos\left( \frac{13\pi}{8} \right) + i\sin\left( \frac{13\pi}{8} \right)

These give the four fourth roots of ii. The statement suggests that two of them are ±1\pm 1 and the other two are ±i\pm i, but the exact values are more complex when expressed in trigonometric form.

Would you like further details or clarification on any part of this?

Here are 5 related questions to explore:

  1. What is De Moivre's Theorem and how is it applied?
  2. How do you convert complex numbers into polar form?
  3. What are other methods to find the roots of a complex number?
  4. Can we generalize this process to find any nn-th root of a complex number?
  5. How do you verify that these four values satisfy z4=iz^4 = i?

Tip: When dealing with complex numbers, always consider expressing them in polar or exponential form for easier manipulation with powers and roots.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Polar Coordinates
Roots of Complex Numbers

Formulas

z_k = \sqrt[4]{r} \cdot \text{cis}\left( \frac{\theta + 2k\pi}{4} \right)
i = \text{cis}\left( \frac{\pi}{2} \right)

Theorems

De Moivre's Theorem

Suitable Grade Level

Undergraduate level (Advanced Algebra or Pre-Calculus)