Math Problem Statement

Using the given information and the time-shifting properties, find the Fourier Transform of the triangular pulses shown in Fig. (b), Fig. (c), and Fig. (d).

Solution

To solve the problem, we will use the given Fourier Transform (FT) of the triangular pulse f(t)f(t) in Fig. (a) and apply time-shifting properties for the other figures (b), (c), and (d).

The FT of the triangular pulse f(t)f(t) in Fig. (a) is given as: F(ω)=1ω2(ejωjωejω1)F(\omega) = \frac{1}{\omega^2} \left( e^{j\omega} - j\omega e^{j\omega} - 1 \right)


Step 1: Time-Shifting Property of Fourier Transform

If f(t)f(t) has the Fourier Transform F(ω)F(\omega), then the time-shifted signal f(tt0)f(t - t_0) has the Fourier Transform: F(ω)ejωt0F(\omega) e^{-j\omega t_0}

Here:

  • t0t_0 is the amount of shift in time.

Step 2: Solving for Figures

(b): Fig. (b) - fb(t)f_b(t)

  • In Fig. (b), the triangular pulse is shifted to the right by t0=1t_0 = 1.
  • Using the time-shifting property: Fb(ω)=F(ω)ejωF_b(\omega) = F(\omega) \cdot e^{-j\omega}

(c): Fig. (c) - fc(t)f_c(t)

  • In Fig. (c), the triangular pulse consists of two shifted pulses:
    • One shifted to the left by t0=1t_0 = -1
    • One shifted to the right by t0=1t_0 = 1
  • The signal can be expressed as: fc(t)=f(t+1)+f(t1)f_c(t) = f(t + 1) + f(t - 1)
  • Using the time-shifting property, the FT of fc(t)f_c(t) is: Fc(ω)=F(ω)ejω+F(ω)ejωF_c(\omega) = F(\omega) e^{j\omega} + F(\omega) e^{-j\omega}
  • Simplify: Fc(ω)=F(ω)(ejω+ejω)F_c(\omega) = F(\omega) \left( e^{j\omega} + e^{-j\omega} \right)
  • Using Euler's formula ejω+ejω=2cos(ω)e^{j\omega} + e^{-j\omega} = 2\cos(\omega), we get: Fc(ω)=2F(ω)cos(ω)F_c(\omega) = 2F(\omega) \cos(\omega)

(d): Fig. (d) - fd(t)f_d(t)

  • In Fig. (d), the triangular pulse is shifted to the left by t0=1t_0 = -1.
  • Using the time-shifting property: Fd(ω)=F(ω)ejωF_d(\omega) = F(\omega) e^{j\omega}

Final Results

The Fourier Transforms for the given signals are:

  1. Fig. (b): Fb(ω)=F(ω)ejωF_b(\omega) = F(\omega) e^{-j\omega}
  2. Fig. (c): Fc(ω)=2F(ω)cos(ω)F_c(\omega) = 2F(\omega) \cos(\omega)
  3. Fig. (d): Fd(ω)=F(ω)ejωF_d(\omega) = F(\omega) e^{j\omega}

Let me know if you would like a more detailed explanation or any clarification!

Here are 5 related questions to expand your understanding:

  1. What is the Fourier Transform of a shifted rectangular pulse?
  2. How does the time-scaling property of FT affect a signal?
  3. What happens to the FT if the triangular pulse is scaled in amplitude?
  4. How can we use convolution properties to solve FTs of composite signals?
  5. How does the phase shift appear in the FT when time-shifting is applied?

Tip: The time-shifting property of Fourier Transform introduces a phase factor ejωt0e^{-j\omega t_0}, which affects only the phase, not the magnitude.

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Math Problem Analysis

Mathematical Concepts

Fourier Transform
Time-Shifting Property
Linear Combination of Signals
Euler's Formula

Formulas

F(ω) = \frac{1}{ω^2} (e^{jω} - jωe^{jω} - 1)
Time-Shifting Property: F(t - t₀) ↔ F(ω)e^{-jωt₀}
e^{jω} + e^{-jω} = 2cos(ω)

Theorems

Time-Shifting Property of Fourier Transform
Superposition Principle in Fourier Transform

Suitable Grade Level

Undergraduate Level (Engineering, Mathematics)