Math Problem Statement

Find the Fourier transform for the rectangular pulse

Solution

The image you provided presents an example of finding the Fourier transform of a rectangular pulse. Let's break down the components of the solution shown in the image:

  1. Definition of x(t)x(t): The function is a rectangular pulse defined by:

    \begin{cases} 1 & \text{for } |t| < \frac{T_p}{2} \\ 0 & \text{for } |t| \geq \frac{T_p}{2} \end{cases}$$ This is equivalent to the **rectangular function** or **rect(t/Tp)**.
  2. Fourier Transform: The solution shows the Fourier transform formula applied to this function: X(jω)=x(t)ejωtdtX(j\omega) = \int_{-\infty}^{\infty} x(t)e^{-j\omega t} dt Here, the limits of integration are adjusted according to the function being non-zero only within the range Tp2tTp2-\frac{T_p}{2} \leq t \leq \frac{T_p}{2}. Hence the integral becomes: X(jω)=Tp2Tp2ejωtdtX(j\omega) = \int_{-\frac{T_p}{2}}^{\frac{T_p}{2}} e^{-j\omega t} dt

  3. Solving the Integral: The Fourier transform of the rectangular pulse is solved through the integration, leading to a well-known result: X(jω)=Tpsinc(ωTp2)X(j\omega) = T_p \cdot \text{sinc} \left( \frac{\omega T_p}{2} \right) where sinc(x)\text{sinc}(x) is the normalized sinc function defined as: sinc(x)=sin(πx)πx\text{sinc}(x) = \frac{\sin(\pi x)}{\pi x}

The resulting Fourier transform shows the characteristic shape of the sinc function, which is often seen for pulse signals.

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Math Problem Analysis

Mathematical Concepts

Fourier Transform
Rectangular Pulse
Sinc Function

Formulas

X(jω) = ∫(from -Tp/2 to Tp/2) e^(-jωt) dt

Theorems

Fourier Transform of a Rectangular Pulse

Suitable Grade Level

College/University (Engineering, Signal Processing)