Math Problem Statement

use DIRECT INTEGRATION to find the Fourier transform G(f) of the signal g(t) (Note: the unit rectangular function has a range between -1/2 and 1/2): g(t)= Π(t-1)-5exp(-2|t+3|)

Solution

To find the Fourier transform G(f)G(f) of the signal g(t)g(t) using direct integration, we first break down the given signal into its components:

g(t)=Π(t1)5exp(2t+3)g(t) = \Pi(t - 1) - 5 \exp(-2|t + 3|)

Here:

  • Π(t1)\Pi(t - 1) is a shifted unit rectangular function centered at t=1t = 1, with a width of 1, spanning from t=0.5t = 0.5 to t=1.5t = 1.5.
  • 5exp(2t+3)5 \exp(-2|t + 3|) is an exponentially decaying signal, symmetrically centered at t=3t = -3.

The Fourier transform G(f)G(f) is defined by the following integral:

G(f)=g(t)ej2πftdtG(f) = \int_{-\infty}^{\infty} g(t) e^{-j 2\pi f t} \, dt

Step 1: Fourier Transform of Π(t1)\Pi(t - 1)

The unit rectangular function Π(t1)\Pi(t - 1) is a shifted version of the standard rectangular function Π(t)\Pi(t), and its Fourier transform is well-known.

Π(t1)is non-zero for0.5t1.5\Pi(t - 1) \quad \text{is non-zero for} \quad 0.5 \leq t \leq 1.5

The Fourier transform of Π(t)\Pi(t) is:

F[Π(t)]=sin(πf)πf\mathcal{F}\left[\Pi(t)\right] = \frac{\sin(\pi f)}{\pi f}

Since the rectangular function is shifted by 1 unit, the Fourier transform will include a phase shift:

F[Π(t1)]=sin(πf)πfej2πf\mathcal{F}\left[\Pi(t - 1)\right] = \frac{\sin(\pi f)}{\pi f} e^{-j 2\pi f}

Step 2: Fourier Transform of 5exp(2t+3)5 \exp(-2|t + 3|)

This is an exponentially decaying function of the form exp(att0)\exp(-a |t - t_0|). The Fourier transform of exp(at)\exp(-a|t|) is:

F[exp(at)]=2aa2+(2πf)2\mathcal{F}\left[\exp(-a |t|)\right] = \frac{2a}{a^2 + (2\pi f)^2}

For 5exp(2t+3)5 \exp(-2|t + 3|), we apply a time shift of t0=3t_0 = -3. The Fourier transform of a shifted exponential decay is:

F[5exp(2t+3)]=104+(2πf)2ej6πf\mathcal{F}\left[5 \exp(-2|t + 3|)\right] = \frac{10}{4 + (2\pi f)^2} e^{j 6 \pi f}

Step 3: Combine the Results

The Fourier transform of g(t)=Π(t1)5exp(2t+3)g(t) = \Pi(t - 1) - 5 \exp(-2|t + 3|) is the sum of the Fourier transforms of the individual components:

G(f)=sin(πf)πfej2πf104+(2πf)2ej6πfG(f) = \frac{\sin(\pi f)}{\pi f} e^{-j 2\pi f} - \frac{10}{4 + (2\pi f)^2} e^{j 6 \pi f}

This is the Fourier transform of the signal g(t)g(t).


Let me know if you would like a deeper explanation or further steps in the process.

Here are 5 related questions for practice:

  1. What is the Fourier transform of Π(t)\Pi(t) without any shifts?
  2. How would you find the Fourier transform of cos(2πt)\cos(2\pi t)?
  3. What is the inverse Fourier transform of sin(πf)πf\frac{\sin(\pi f)}{\pi f}?
  4. How does time shifting affect the Fourier transform of a signal?
  5. What are the properties of Fourier transforms for even and odd functions?

Tip:

When performing Fourier transforms on shifted signals, remember to account for phase shifts, as they appear as complex exponentials in the frequency domain.

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Math Problem Analysis

Mathematical Concepts

Fourier Transform
Unit Rectangular Function
Exponential Decay
Time Shifting in Signals

Formulas

G(f) = ∫ g(t) e^{-j 2π f t} dt
Fourier Transform of Π(t): F[Π(t)] = sin(π f) / (π f)
Fourier Transform of exp(-a |t|): F[exp(-a |t|)] = 2a / (a^2 + (2π f)^2)

Theorems

Fourier Transform Time Shift Property
Fourier Transform Scaling Theorem

Suitable Grade Level

Undergraduate level (Engineering or Physics)