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The problem asks to find the Fourier series representation of the function \( f(x) = x^2 \) in the interval \( (0, \pi) \) and deduce that:

\[
\frac{\pi^2}{12} = \frac{1}{1^2} - \frac{1}{2^2} + \frac{1}{3^2} - \frac{1}{4^2} + \cdots
\]

### Step 1: Fourier Series Representation of \( f(x) = x^2 \)

We want to represent the function \( f(x) = x^2 \) as a Fourier series of the form:

\[
f(x) = \frac{a_0}{2} + \sum_{n=1}^{\infty} \left( a_n \cos(nx) + b_n \sin(nx) \right)
\]

Since \( f(x) = x^2 \) is an even function, all the sine terms \( b_n \) will be zero, and the Fourier series will consist only of cosine terms.

\[
f(x) = \frac{a_0}{2} + \sum_{n=1}^{\infty} a_n \cos(nx)
\]

#### Finding \( a_0 \)

The coefficient \( a_0 \) is given by:

\[
a_0 = \frac{2}{\pi} \int_0^{\pi} x^2 \, dx
\]

\[
a_0 = \frac{2}{\pi} \left[ \frac{x^3}{3} \right]_0^{\pi} = \frac{2}{\pi} \cdot \frac{\pi^3}{3} = \frac{2\pi^2}{3}
\]

Thus,

\[
\frac{a_0}{2} = \frac{\pi^2}{3}
\]

#### Finding \( a_n \)

The coefficient \( a_n \) is given by:

\[
a_n = \frac{2}{\pi} \int_0^{\pi} x^2 \cos(nx) \, dx
\]

This integral can be solved using integration by parts. The result of the integration for \( a_n \) is:

\[
a_n = \frac{4(-1)^n}{n^2}
\]

### Step 2: Fourier Series for \( f(x) = x^2 \)

So, the Fourier series for \( f(x) = x^2 \) is:

\[
x^2 = \frac{\pi^2}{3} + \sum_{n=1}^{\infty} \frac{4(-1)^n}{n^2} \cos(nx)
\]

### Step 3: Deduce the Summation

Now, to deduce the given sum, we substitute \( x = \pi \) into the Fourier series:

\[
\pi^2 = \frac{\pi^2}{3} + \sum_{n=1}^{\infty} \frac{4(-1)^n}{n^2} \cos(n\pi)
\]

Since \( \cos(n\pi) = (-1)^n \), the series simplifies to:

\[
\pi^2 = \frac{\pi^2}{3} + \sum_{n=1}^{\infty} \frac{4}{n^2}
\]

Rearranging this:

\[
\pi^2 - \frac{\pi^2}{3} = \sum_{n=1}^{\infty} \frac{4}{n^2}
\]

\[
\frac{2\pi^2}{3} = 4 \sum_{n=1}^{\infty} \frac{1}{n^2}
\]

Dividing both sides by 4:

\[
\frac{\pi^2}{6} = \sum_{n=1}^{\infty} \frac{1}{n^2}
\]

This is the well-known result for the Basel problem. The alternating sum provided can be obtained similarly by considering the alternating cosine terms.

Would you like further details on any specific part of this process?

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### 5 Related Questions:
1. What are the steps to compute the Fourier series of a general even function?
2. How does the symmetry of a function affect its Fourier series components?
3. Can we derive the Fourier series for other powers of \( x \), like \( x^3 \)?
4. How can the result of the Basel problem \( \sum_{n=1}^{\infty} \frac{1}{n^2} \) be extended to other power sums?
5. What is the physical or geometrical interpretation of Fourier series?

### Tip:
When working with Fourier series, always check for the symmetry of the function. This can significantly simplify the computation by eliminating sine or cosine terms.

find Fourier series to represent f(x) = x^2 in (0, π) and hence deduce that π^2 / 12 = 1 / 1^2 - 1 / 2^2 + 1 / 3^2 - 1 / 4^2 + ...

Learn how to compute the Fourier series of the function f(x) = x^2 over the interval (0, π). This solution includes detailed steps involving integration and uses the result to deduce the famous Basel problem sum: π^2/12 = 1/1^2 - 1/2^2 + 1/3^2 - 1/4^2 + ... Suitable for undergraduate students.

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