Math Problem Statement

Interval integral Fourier series

Interval integral Fourier series

Solution

The function F(x)F(x) is a piecewise function defined as:

3, & 0 < x < 5 \\ -3, & -5 < x < 0 \end{cases}$$ ### To compute the Fourier Series The Fourier series for a periodic function is given by: $$F(x) = \frac{a_0}{2} + \sum_{n=1}^{\infty} \left( a_n \cos \left( \frac{2\pi n x}{T} \right) + b_n \sin \left( \frac{2\pi n x}{T} \right) \right)$$ Where $$T$$ is the period of the function, and the coefficients $$a_0$$, $$a_n$$, and $$b_n$$ are determined as follows: - $$a_0$$ (DC term) is calculated by: $$a_0 = \frac{2}{T} \int_{-\frac{T}{2}}^{\frac{T}{2}} F(x) \, dx$$ - $$a_n$$ (cosine coefficients) are calculated by: $$a_n = \frac{2}{T} \int_{-\frac{T}{2}}^{\frac{T}{2}} F(x) \cos \left( \frac{2\pi n x}{T} \right) \, dx$$ - $$b_n$$ (sine coefficients) are calculated by: $$b_n = \frac{2}{T} \int_{-\frac{T}{2}}^{\frac{T}{2}} F(x) \sin \left( \frac{2\pi n x}{T} \right) \, dx$$ ### Steps: 1. **Determine the period $$T$$**: Since the function is defined in the interval $$-5 < x < 5$$, the period $$T = 10$$. 2. **Calculate $$a_0$$ (DC term)**: The average value of the function over one period. 3. **Calculate $$a_n$$ and $$b_n$$** using the above formulas. Shall we proceed with calculating the Fourier series terms in detail?

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Piecewise Functions
Fourier Series

Formulas

Fourier series: F(x) = a_0/2 + sum(a_n cos(2πnx/T) + b_n sin(2πnx/T))
DC term: a_0 = (2/T) ∫ F(x) dx
Cosine coefficients: a_n = (2/T) ∫ F(x) cos(2πnx/T) dx
Sine coefficients: b_n = (2/T) ∫ F(x) sin(2πnx/T) dx

Theorems

Fourier Series Theorem

Suitable Grade Level

College Level