https://file.aiquickdraw.com/mathbot/file/1727302306872cmhysbji.jpg

From the image provided, we need to figure out Latisha's house number using the given clues:

### Clues:
1. **My house number has four digits.**
2. **Each digit is greater than the digit just to its left.**
3. **The first digit at the left is an even number.**
4. **The difference between the first digit and the second is 1.**
5. **The last digit is one more than the third digit.**
6. **The four digits add up to 20.**

### Let's break this down:

1. The number has four digits.
2. The digits increase from left to right.
3. The first digit is even.
4. The difference between the first and second digits is 1.
5. The last digit is one more than the third.
6. The sum of all digits equals 20.

### Let’s try to find the solution step by step:
- The first digit is even, so possibilities are \(2, 4, 6, 8\).
- The second digit is 1 greater than the first, so if the first digit is \(2\), the second digit would be \(3\), and so on.
- The last digit is one more than the third, so if the third digit is \(x\), the last digit is \(x + 1\).
- The total sum of all digits must be 20.

Let's now solve this.

Let the digits be \(a, b, c, d\), where:
- \(a\) is even.
- \(b = a + 1\).
- \(d = c + 1\).
- \(a + b + c + d = 20\).

Substitute the values of \(b\) and \(d\) into the equation:
\[ a + (a + 1) + c + (c + 1) = 20 \]
Simplifying:
\[ 2a + 2c + 2 = 20 \]
\[ 2a + 2c = 18 \]
\[ a + c = 9 \]

Now, since \(a\) is an even number, possible pairs of \(a\) and \(c\) that satisfy this equation are:
- \(a = 2\), \(c = 7\)
- \(a = 4\), \(c = 5\)

### Testing these pairs:
1. **For \(a = 2\) and \(c = 7\):**
   - \(b = a + 1 = 3\),
   - \(d = c + 1 = 8\).
   - Digits are \(2, 3, 7, 8\).
   - Sum is \(2 + 3 + 7 + 8 = 20\), which satisfies the condition.
   - All other clues are satisfied.

Thus, Latisha's house number is **2378**.

Would you like more details on the solution, or have any other questions?

### Here are 5 related questions you might want to explore:
1. How can you generate other sets of numbers that satisfy similar conditions?
2. How would the solution change if one of the conditions were different, such as the sum being 25?
3. Can this puzzle be solved algebraically for different sums and digit constraints?
4. What strategies are best for solving digit puzzles systematically?
5. How does the use of constraints like "digits increase" help in narrowing down possible solutions?

### Tip:
When solving puzzles with several conditions, try isolating individual variables or relationships and gradually substitute them into your equations. This stepwise approach prevents overlooking any clues.

Latisha invited me to a mystery party. The first mystery is to figure out her house number! Follow the clues on the invitation to find Latisha’s house number.

Learn how to solve a mystery house number puzzle using logic and number patterns. Follow clues such as digit sums, increasing sequences, and even numbers to crack this engaging riddle. Suitable for students in Grades 4-6.

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