Math Problem Statement

A square foundation (B x B) has to be constructed 1.2 m below the ground surface. Assume that following properties: 𝛾 = 16.50 kN/m3 𝛾𝑠𝑎𝑡 = 18.45 kN/m3 ∅ ′ = 30 Degree C’ = 10 kN/m2 The water table is 0.50 m below the bottom of the footing. The gross allowable load with factor of safety of 3.00 is 665 kN. Determine the size of the foundation.

Solution

To determine the size of the foundation for the square footing, we need to calculate the ultimate bearing capacity of the soil and use it to find the required footing size, BB.

Step-by-Step Approach:

  1. Given Data:

    • Foundation depth: Df=1.2mD_f = 1.2 \, \text{m}
    • Soil unit weight (above the water table): γ=16.50kN/m3\gamma = 16.50 \, \text{kN/m}^3
    • Saturated soil unit weight (below the water table): γsat=18.45kN/m3\gamma_{\text{sat}} = 18.45 \, \text{kN/m}^3
    • Friction angle: ϕ=30\phi' = 30^\circ
    • Cohesion: C=10kN/m2C' = 10 \, \text{kN/m}^2
    • Factor of safety: Fs=3.00F_s = 3.00
    • Gross allowable load: Qallow=665kNQ_{\text{allow}} = 665 \, \text{kN}
    • Water table depth below footing: 0.5m0.5 \, \text{m}
  2. Determine the Ultimate Bearing Capacity (Using Terzaghi's Equation for Square Footing):

    The ultimate bearing capacity quq_u for a square footing is given by the formula:

    qu=CNc+γDfNq+0.5γBNγq_u = C'N_c + \gamma D_f N_q + 0.5 \gamma' B N_{\gamma}

    Where:

    • NcN_c, NqN_q, NγN_{\gamma} are bearing capacity factors dependent on the friction angle ϕ\phi'.
    • γ\gamma' is the effective unit weight of the soil.

    Let's calculate each term step by step.

  3. Bearing Capacity Factors:

    Using typical values for ϕ=30\phi' = 30^\circ:

    • Nc=30.14N_c = 30.14
    • Nq=18.4N_q = 18.4
    • Nγ=15.1N_{\gamma} = 15.1
  4. Effective Unit Weight γ\gamma':

    Since the water table is 0.5 m below the footing, the soil below the water table will be partially submerged. The effective unit weight γ\gamma' is calculated as:

    γ=γsatγw\gamma' = \gamma_{\text{sat}} - \gamma_w Where γw\gamma_w is the unit weight of water, typically 9.81kN/m39.81 \, \text{kN/m}^3.

    γ=18.459.81=8.64kN/m3\gamma' = 18.45 - 9.81 = 8.64 \, \text{kN/m}^3

  5. Ultimate Bearing Capacity quq_u:

    The formula for ultimate bearing capacity is applied for the unknown size BB of the footing. Now, let's assume a size BB, and solve the equation.

I'll calculate the value of BB next.The size of the square foundation, BB, is approximately 20.38 meters.

Would you like more details or have any other questions?

Here are some additional questions that might help expand on this topic:

  1. How would changes in the water table level affect the foundation size?
  2. What are the implications of using a different soil friction angle ϕ\phi'?
  3. How does the factor of safety influence the design of the foundation?
  4. What happens to the foundation design if the cohesion CC' increases?
  5. How can you adjust the footing design if the load were to increase beyond 665 kN?

Tip: Always consider the position of the water table when designing foundations, as it significantly impacts soil behavior and bearing capacity.

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Math Problem Analysis

Mathematical Concepts

Geotechnical Engineering
Bearing Capacity
Soil Mechanics
Foundation Design

Formulas

Ultimate Bearing Capacity: qu = C'Nc + γDfNq + 0.5γ'BNγ
Effective Unit Weight: γ' = γsat - γw

Theorems

Terzaghi’s Bearing Capacity Theory

Suitable Grade Level

Undergraduate Civil Engineering