Math Problem Statement

How many words can be formed with the help of 3 consonants and 2 vowels, such that no two consonants are adjacent ?

Solution

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Permutations
Combinations

Formulas

Combination formula: \binom{n}{k} = \frac{n!}{k!(n-k)!}
Permutations of vowels: 2!
Permutations of consonants in gaps: 3!

Theorems

Basic Counting Principle

Suitable Grade Level

Grades 9-12