Math Problem Statement
How many words can be formed with the help of 3 consonants and 2 vowels, such that no two consonants are adjacent ?
Solution
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Math Problem Analysis
Mathematical Concepts
Combinatorics
Permutations
Combinations
Formulas
Combination formula: \binom{n}{k} = \frac{n!}{k!(n-k)!}
Permutations of vowels: 2!
Permutations of consonants in gaps: 3!
Theorems
Basic Counting Principle
Suitable Grade Level
Grades 9-12
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