Math Problem Statement

The following time series data show the number of lightning strikes in a particular county for the most recent seven months.

Month

1

2

3

4

5

6

7

Value

31

20

27

19

26

30

22

(a)

Compute MSE using the most recent value as the forecast for the next period.

MSE =

What is the forecast for month 8?

(b)

Compute MSE using the average of all the data available as the forecast for the next period. (Round your answer to two decimal places.)

MSE =

What is the forecast for month 8?

(c)

Which method appears to provide the better forecast?

The average of all the previous values provides a better forecast, because its MSE is smaller than the MSE using the most recent value.The most recent value provides a better forecast, because its forecast for month 8 is smaller than the month 8 forecast using the average of all the previous values.     The most recent value provides a better forecast, because its MSE is smaller than the MSE using the average of all the previous values.The average of all the previous values provides a better forecast, because its forecast for month 8 is larger than the month 8 forecast using the most recent value.

Solution

(a) Compute MSE using the most recent value as the forecast for the next period.

The forecast for each month is the value of the previous month. Calculate the Mean Squared Error (MSE) using:

MSE=1ni=1n(yiy^i)2\text{MSE} = \frac{1}{n}\sum_{i=1}^{n} (y_i - \hat{y}_i)^2

Where yiy_i is the actual value, and y^i\hat{y}_i is the forecasted value.

  • Month 2 forecast = Value from Month 1 = 31
  • Month 3 forecast = Value from Month 2 = 20
  • Month 4 forecast = Value from Month 3 = 27
  • Month 5 forecast = Value from Month 4 = 19
  • Month 6 forecast = Value from Month 5 = 26
  • Month 7 forecast = Value from Month 6 = 30

Calculate squared errors:

Squared Error for Month 2=(2031)2=121\text{Squared Error for Month 2} = (20 - 31)^2 = 121 Squared Error for Month 3=(2720)2=49\text{Squared Error for Month 3} = (27 - 20)^2 = 49 Squared Error for Month 4=(1927)2=64\text{Squared Error for Month 4} = (19 - 27)^2 = 64 Squared Error for Month 5=(2619)2=49\text{Squared Error for Month 5} = (26 - 19)^2 = 49 Squared Error for Month 6=(3026)2=16\text{Squared Error for Month 6} = (30 - 26)^2 = 16 Squared Error for Month 7=(2230)2=64\text{Squared Error for Month 7} = (22 - 30)^2 = 64

Sum of squared errors: 121+49+64+49+16+64=363121 + 49 + 64 + 49 + 16 + 64 = 363

Number of periods (nn) = 6.

MSE=3636=60.5\text{MSE} = \frac{363}{6} = 60.5

MSE (Most Recent Value Forecast) = 60.5

Forecast for Month 8:

The forecast is the value from Month 7 = 22.


(b) Compute MSE using the average of all available data as the forecast.

The forecast for each month is the average of all data available up to that point.

  1. Month 2 forecast = Average of Month 1 = 3131
  2. Month 3 forecast = Average of Months 1 & 2 = 31+202=25.5\frac{31 + 20}{2} = 25.5
  3. Month 4 forecast = Average of Months 1–3 = 31+20+273=26\frac{31 + 20 + 27}{3} = 26
  4. Month 5 forecast = Average of Months 1–4 = 31+20+27+194=24.25\frac{31 + 20 + 27 + 19}{4} = 24.25
  5. Month 6 forecast = Average of Months 1–5 = 31+20+27+19+265=24.6\frac{31 + 20 + 27 + 19 + 26}{5} = 24.6
  6. Month 7 forecast = Average of Months 1–6 = 31+20+27+19+26+306=25.5\frac{31 + 20 + 27 + 19 + 26 + 30}{6} = 25.5

Calculate squared errors:

Squared Error for Month 2=(2031)2=121\text{Squared Error for Month 2} = (20 - 31)^2 = 121 Squared Error for Month 3=(2725.5)2=2.25\text{Squared Error for Month 3} = (27 - 25.5)^2 = 2.25 Squared Error for Month 4=(1926)2=49\text{Squared Error for Month 4} = (19 - 26)^2 = 49 Squared Error for Month 5=(2624.25)2=3.06\text{Squared Error for Month 5} = (26 - 24.25)^2 = 3.06 Squared Error for Month 6=(3024.6)2=29.16\text{Squared Error for Month 6} = (30 - 24.6)^2 = 29.16 Squared Error for Month 7=(2225.5)2=12.25\text{Squared Error for Month 7} = (22 - 25.5)^2 = 12.25

Sum of squared errors: 121+2.25+49+3.06+29.16+12.25=216.72121 + 2.25 + 49 + 3.06 + 29.16 + 12.25 = 216.72

Number of periods (nn) = 6.

MSE=216.726=36.12\text{MSE} = \frac{216.72}{6} = 36.12

MSE (Average Forecast) = 36.12

Forecast for Month 8:

The forecast is the average of all seven months: Average=31+20+27+19+26+30+227=1757=25\text{Average} = \frac{31 + 20 + 27 + 19 + 26 + 30 + 22}{7} = \frac{175}{7} = 25


(c) Which method provides the better forecast?

Conclusion: The average forecast has a lower MSE (36.12) than the most recent value forecast (60.5), so the average of all previous values provides a better forecast.


Summary of Results:

  1. MSE (Most Recent Value) = 60.5
  2. Forecast for Month 8 (Most Recent Value) = 22
  3. MSE (Average) = 36.12
  4. Forecast for Month 8 (Average) = 25
  5. Better Forecast Method: Average (smaller MSE).

Would you like detailed steps for any part?

Questions to Explore:

  1. How are different forecasting methods useful in real-world scenarios?
  2. Why does MSE emphasize large errors more than small errors?
  3. What other accuracy metrics could we use instead of MSE?
  4. Could we use weighted averages for better forecasting? How?
  5. How would adding more data points change the forecast accuracy?

Tip: Always compare MSE values when choosing the best forecasting method!

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Math Problem Analysis

Mathematical Concepts

Time Series Analysis
Forecasting
Mean Squared Error (MSE)

Formulas

MSE = (1/n) * Σ(y_i - ŷ_i)^2
Forecasting using recent value
Forecasting using data average

Theorems

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Suitable Grade Level

Grades 11-12