Math Problem Statement

Two identical blocks, X and Y, each of mass m, lie on a frictionless horizontal surface with their adjacent faces in contact. If a horizontal force F is applied to X, which statement is true? (Options: A, B, C, D)

Solution

The exercise shows two identical blocks, XX and YY, each of mass mm, in contact with each other on a frictionless horizontal surface. A horizontal force FF is applied to block XX. The question asks which statement is true under these conditions:

  1. Analysis of Statements:
    • Statement A: "X will exert a force of magnitude FF on Y."

      • This is incorrect because the force FF applied to block XX is used to accelerate both XX and YY, so the force exerted by XX on YY would actually be less than FF.
    • Statement B: "X will undergo an acceleration of F/mF/m."

      • This is also incorrect. The combined mass of the two blocks (2m)(2m) will accelerate together due to the force FF. Therefore, the acceleration aa of both blocks is a=F2ma = \frac{F}{2m}.
    • Statement C: "X will exert a force of F/2F/2 on Y."

      • This is correct. Since both blocks accelerate at F2m\frac{F}{2m}, the force that XX exerts on YY is indeed F2\frac{F}{2}, which is the force required

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Math Problem Analysis

Mathematical Concepts

Newton's Laws of Motion
Force
Acceleration

Formulas

Newton's Second Law: F = ma
Acceleration of combined mass: a = F / (2m)
Force exerted by X on Y: F_XY = F / 2

Theorems

Newton's Third Law of Motion

Suitable Grade Level

Grades 10-12