Math Problem Statement

a force of f=90 N is extended on mass m1. both m1 and m2 accelerate to the right at 3m/s^2 along the frictionless surface. the force F makes an angle of 25 degrees to the horizontal. calculate the force that the horizontal surface exerts on mass m1 (m2=10kg)

Solution

We are given the following:

  • Force F=90NF = 90 \, \text{N}, applied at an angle of 2525^\circ to the horizontal.
  • Mass m2=10kgm_2 = 10 \, \text{kg}.
  • The acceleration a=3m/s2a = 3 \, \text{m/s}^2 for both masses m1m_1 and m2m_2.
  • The surface is frictionless, so we can ignore frictional forces.

To calculate the force that the horizontal surface exerts on mass m1m_1, we will find both the horizontal and vertical components of the applied force and use Newton's second law.

Step 1: Horizontal component of the applied force

The horizontal component of force FxF_x is responsible for accelerating both masses:

Fx=Fcos(25)F_x = F \cdot \cos(25^\circ) This force acts on both m1m_1 and m2m_2, and thus we apply Newton’s second law:

Fx=(m1+m2)aF_x = (m_1 + m_2) \cdot a

Step 2: Solve for m1m_1

Rearranging the above equation to solve for m1m_1:

m1=Fxam2m_1 = \frac{F_x}{a} - m_2

Substitute FxF_x and solve for m1m_1:

m1=Fcos(25)am2m_1 = \frac{F \cdot \cos(25^\circ)}{a} - m_2

Step 3: Vertical forces

The vertical component of the applied force FyF_y is:

Fy=Fsin(25)F_y = F \cdot \sin(25^\circ)

The normal force NN exerted by the horizontal surface on m1m_1 balances the vertical forces acting on m1m_1, i.e., the gravitational force m1gm_1g and the vertical component FyF_y:

N=m1gFyN = m_1 g - F_y

Let’s calculate each of these steps.The mass m1m_1 is approximately 17.19kg17.19 \, \text{kg}, and the normal force that the horizontal surface exerts on mass m1m_1 is approximately 130.59N130.59 \, \text{N}.

Do you want any more details or have further questions?

Here are some related questions:

  1. How does the angle of applied force affect the normal force on the object?
  2. What would change if there were friction between the masses and the surface?
  3. How would the problem change if the masses were connected by a rope?
  4. Can you calculate the total force exerted by the horizontal surface on both masses?
  5. How would increasing the acceleration affect the forces in the system?

Tip: Breaking forces into components simplifies solving problems involving angles. Always resolve vectors into horizontal and vertical components.

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Math Problem Analysis

Mathematical Concepts

Newton's Second Law
Vector Decomposition
Forces and Motion

Formulas

F_x = F * cos(θ)
F_x = (m1 + m2) * a
m1 = (F * cos(θ) / a) - m2
F_y = F * sin(θ)
N = m1 * g - F_y

Theorems

Newton's Second Law

Suitable Grade Level

Grades 11-12