It looks like you uploaded an image of a physics/mechanics question involving fluids. I will analyze the content and solve the problems based on the information provided. Let me interpret and solve it for you.

Problem Analysis:

First Question:

• A1 = 1 cm², A2 = 20 cm²
• Mass placed on A1 is 1.25 kg.
• Calculate the force exerted on A2, assuming the fluid density is $\rho = 1000 \, \text{kg/m}^3$.

Second Question:

• There is a U-shaped container with two different fluids at equilibrium. Given the geometry and liquid levels, find the density $\rho_r$ of the second fluid.

Let me calculate these one by one.# Calculations for the provided problems

Constants and knowns for first problem

A1 = 1 # cm^2 A2 = 20 # cm^2 mass_A1 = 1.25 # kg density_fluid = 1000 # kg/m^3 g = 9.81 # acceleration due to gravity (m/s^2)

Converting A1 and A2 to m^2

A1_m2 = A1 * 1e-4 # m^2 A2_m2 = A2 * 1e-4 # m^2

Force exerted on A1

force_A1 = mass_A1 * g # F = m * g

Pressure exerted by A1

pressure = force_A1 / A1_m2 # P = F / A

Force exerted on A2

force_A2 = pressure * A2_m2 # F = P * A

force_A2245.25245.25successFor the first question, the force exerted on $A_2$ is 245.25 N.

Now, I will proceed to calculate the second question regarding the equilibrium of fluids in the U-shaped container.# Constants and knowns for second problem h1 = 5 # height of fluid 1 (cm) h2 = 7 # height of fluid 2 (cm) h3 = 2 # height of fluid 3 (cm) rho_1 = 2 # density of fluid 1 (g/cm^3)

Fluid density relationship at equilibrium

Pressure on both sides must be equal

rho_1 * g * h1 = rho_r * g * h2 + rho_1 * g * h3

Simplify and solve for rho_r

rho_r = (rho_1 * h1 - rho_1 * h3) / h2 # density of fluid 2 (g/cm^3)

rho_r0.85714285714285710.8571428571428571successFor