Math Problem Statement

Solve this

Solve the equation: ⌊√n + √(n + 1) + √(n + 2)⌋ = ⌊√(9n + 8)⌋

Solution

The given equation is:

n+n+1+n+2=9n+8\left\lfloor \sqrt{n} + \sqrt{n+1} + \sqrt{n+2} \right\rfloor = \left\lfloor \sqrt{9n + 8} \right\rfloor

Where x\lfloor x \rfloor represents the floor function, which gives the greatest integer less than or equal to xx.

To solve this equation, we need to explore the possible integer values of nn such that the floor values of both sides are equal.

Steps:

  1. Analyze the behavior of both sides:

    • The left side involves three square roots added together.
    • The right side simplifies to a single square root function of nn.
  2. Approximate small values of nn: We will try integer values of nn to see when the equation holds.

Let's start solving this through approximations:

For n=0n = 0:

0+1+2=0+1+1.414=2.414=2\left\lfloor \sqrt{0} + \sqrt{1} + \sqrt{2} \right\rfloor = \left\lfloor 0 + 1 + 1.414 \right\rfloor = \left\lfloor 2.414 \right\rfloor = 2 9(0)+8=8=2.828=2\left\lfloor \sqrt{9(0) + 8} \right\rfloor = \left\lfloor \sqrt{8} \right\rfloor = \left\lfloor 2.828 \right\rfloor = 2 Thus, n=0n = 0 is a solution.

For n=1n = 1:

1+2+3=1+1.414+1.732=4.146=4\left\lfloor \sqrt{1} + \sqrt{2} + \sqrt{3} \right\rfloor = \left\lfloor 1 + 1.414 + 1.732 \right\rfloor = \left\lfloor 4.146 \right\rfloor = 4 9(1)+8=17=4.123=4\left\lfloor \sqrt{9(1) + 8} \right\rfloor = \left\lfloor \sqrt{17} \right\rfloor = \left\lfloor 4.123 \right\rfloor = 4 Thus, n=1n = 1 is also a solution.

For n=2n = 2:

2+3+4=1.414+1.732+2=5.146=5\left\lfloor \sqrt{2} + \sqrt{3} + \sqrt{4} \right\rfloor = \left\lfloor 1.414 + 1.732 + 2 \right\rfloor = \left\lfloor 5.146 \right\rfloor = 5 9(2)+8=26=5.099=5\left\lfloor \sqrt{9(2) + 8} \right\rfloor = \left\lfloor \sqrt{26} \right\rfloor = \left\lfloor 5.099 \right\rfloor = 5 Thus, n=2n = 2 is another solution.

Conclusion:

The values of n=0,1,2n = 0, 1, 2 satisfy the equation. Therefore, these are the solutions to the equation.

Let me know if you'd like further clarification, and here are 5 related questions to explore:

  1. How does the floor function affect the solution process?
  2. Why is it important to test small values of nn first in equations like this?
  3. Can this equation have solutions for larger values of nn?
  4. What methods can be used to approximate the values of square roots without a calculator?
  5. How does the presence of square roots in the equation impact the behavior of the functions?

Tip: When dealing with floor functions and square roots, always check boundary values carefully to ensure accuracy in approximations.

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Math Problem Analysis

Mathematical Concepts

Square Roots
Floor Function
Inequalities

Formulas

Floor function: ⌊x⌋ = greatest integer less than or equal to x
Square root function

Theorems

Properties of square roots
Floor function properties

Suitable Grade Level

Grades 10-12