Math Problem Statement
Solution
Let's first break down the task based on the data provided:
The scores of 13 students in ascending order are:
Step 1: Five-number summary
The five-number summary consists of:
- Minimum: The smallest number in the dataset.
- Lower Quartile (Q1): The 25th percentile, which is the median of the lower half of the data.
- Median (Q2): The middle number in the dataset.
- Upper Quartile (Q3): The 75th percentile, which is the median of the upper half of the data.
- Maximum: The largest number in the dataset.
Minimum and Maximum
- Minimum: 63
- Maximum: 94
Median (Q2)
The dataset has 13 numbers, so the median is the 7th number.
- Median: 82
Lower Quartile (Q1)
The lower half of the data (excluding the median) is: The median of this subset is the average of the 3rd and 4th numbers:
Upper Quartile (Q3)
The upper half of the data (excluding the median) is: The median of this subset is the 3rd number:
Step 2: Interquartile Range (IQR)
The interquartile range is given by:
Final Results:
- Minimum: 63
- Lower Quartile (Q1): 73
- Median (Q2): 82
- Upper Quartile (Q3): 87
- Maximum: 94
- Interquartile Range (IQR): 14
Would you like more details on any of these calculations?
Here are 5 related questions to expand on this:
- How is the interquartile range useful in statistics?
- What do outliers look like using the five-number summary and IQR?
- How would you create a box plot using this five-number summary?
- What other methods could be used to describe the spread of data?
- How does the size of the IQR compare to the overall range of this dataset?
Tip: The interquartile range (IQR) helps you understand the spread of the middle 50% of your data. It's useful for identifying outliers!
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Math Problem Analysis
Mathematical Concepts
Statistics
Five-Number Summary
Interquartile Range
Formulas
Lower Quartile (Q1) = Median of lower half of the data
Upper Quartile (Q3) = Median of upper half of the data
Interquartile Range (IQR) = Q3 - Q1
Theorems
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Suitable Grade Level
Grades 6-8