Math Problem Statement

Use finite approximation to estimate the area under the graph of f(x) = 5x^2 and above the graph of f(x) = 0 from x_0 = 0 to x_n = 10 using: i) a lower sum with two rectangles of equal width. ii) a lower sum with four rectangles of equal width. iii) an upper sum with two rectangles of equal width. iv) an upper sum with four rectangles of equal width.

Solution

To solve this problem, we need to approximate the area under the curve of f(x)=5x2f(x) = 5x^2 from x0=0x_0 = 0 to xn=10x_n = 10 using finite approximations. We will calculate both the lower and upper sums with different numbers of rectangles as specified.

Given f(x)=5x2f(x) = 5x^2, here’s how we proceed with each part:

Part i: Lower sum with two rectangles of equal width

  1. Divide the interval [0,10][0, 10] into two subintervals: [0,5][0, 5] and [5,10][5, 10].
  2. The width of each rectangle is Δx=5\Delta x = 5.
  3. For a lower sum, we evaluate f(x)f(x) at the left endpoints:
    • For the first rectangle, x=0x = 0: f(0)=5×02=0f(0) = 5 \times 0^2 = 0
    • For the second rectangle, x=5x = 5: f(5)=5×52=125f(5) = 5 \times 5^2 = 125
  4. The lower sum L2L_2 is: L2=f(0)Δx+f(5)Δx=05+1255=625L_2 = f(0) \cdot \Delta x + f(5) \cdot \Delta x = 0 \cdot 5 + 125 \cdot 5 = 625

Part ii: Lower sum with four rectangles of equal width

  1. Divide the interval [0,10][0, 10] into four subintervals: [0,2.5][0, 2.5], [2.5,5][2.5, 5], [5,7.5][5, 7.5], and [7.5,10][7.5, 10].
  2. The width of each rectangle is Δx=2.5\Delta x = 2.5.
  3. For a lower sum, we evaluate f(x)f(x) at the left endpoints:
    • f(0)=0f(0) = 0
    • f(2.5)=5×(2.5)2=31.25f(2.5) = 5 \times (2.5)^2 = 31.25
    • f(5)=125f(5) = 125
    • f(7.5)=5×(7.5)2=281.25f(7.5) = 5 \times (7.5)^2 = 281.25
  4. The lower sum L4L_4 is: = 0 \cdot 2.5 + 31.25 \cdot 2.5 + 125 \cdot 2.5 + 281.25 \cdot 2.5 = 1093.75$$

Part iii: Upper sum with two rectangles of equal width

  1. Divide the interval [0,10][0, 10] into two subintervals: [0,5][0, 5] and [5,10][5, 10].
  2. The width of each rectangle is Δx=5\Delta x = 5.
  3. For an upper sum, we evaluate f(x)f(x) at the right endpoints:
    • For the first rectangle, x=5x = 5: f(5)=125f(5) = 125
    • For the second rectangle, x=10x = 10: f(10)=5×102=500f(10) = 5 \times 10^2 = 500
  4. The upper sum U2U_2 is: U2=f(5)Δx+f(10)Δx=1255+5005=3125U_2 = f(5) \cdot \Delta x + f(10) \cdot \Delta x = 125 \cdot 5 + 500 \cdot 5 = 3125

Part iv: Upper sum with four rectangles of equal width

  1. Divide the interval [0,10][0, 10] into four subintervals: [0,2.5][0, 2.5], [2.5,5][2.5, 5], [5,7.5][5, 7.5], and [7.5,10][7.5, 10].
  2. The width of each rectangle is Δx=2.5\Delta x = 2.5.
  3. For an upper sum, we evaluate f(x)f(x) at the right endpoints:
    • f(2.5)=31.25f(2.5) = 31.25
    • f(5)=125f(5) = 125
    • f(7.5)=281.25f(7.5) = 281.25
    • f(10)=500f(10) = 500
  4. The upper sum U4U_4 is: = 31.25 \cdot 2.5 + 125 \cdot 2.5 + 281.25 \cdot 2.5 + 500 \cdot 2.5 = 2343.75$$

Would you like more details or have any questions?


Here are some related questions for further exploration:

  1. How does increasing the number of rectangles affect the accuracy of the approximation?
  2. How would the calculation change if f(x)f(x) was a different function?
  3. What is the actual integral of f(x)=5x2f(x) = 5x^2 from 0 to 10, and how do the approximations compare?
  4. How could you set up a Riemann sum for this function and interval?
  5. What are the implications of using the midpoint for each interval instead?

Tip: As the number of rectangles increases in finite approximations, the approximation generally becomes closer to the true area (the definite integral), especially if the function is continuous and well-behaved over the interval.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Finite Approximation
Riemann Sums
Area Under Curve
Quadratic Functions

Formulas

Area ≈ Sum of Rectangle Areas
Lower Sum: Use left endpoint values for height of rectangles
Upper Sum: Use right endpoint values for height of rectangles
f(x) = 5x^2 for function evaluation

Theorems

Riemann Sum Approximation

Suitable Grade Level

Grades 11-12