Find the y-intercept of the following equation:

y = x2 + 2x + 7

To find the y-intercept of the equation \( y = x^2 + 2x + 7 \), we need to set \( x = 0 \) and solve for \( y \).

\[
y = (0)^2 + 2(0) + 7 = 0 + 0 + 7 = 7
\]

Thus, the y-intercept is:

\[
y = 7
\]

Would you like a more detailed explanation or have any further questions?

Here are 5 related questions that might help deepen your understanding:

1. How do you find the x-intercepts of the equation \( y = x^2 + 2x + 7 \)?
2. What is the vertex form of the quadratic equation \( y = x^2 + 2x + 7 \)?
3. How would you determine the axis of symmetry for this quadratic equation?
4. Can you graph the equation \( y = x^2 + 2x + 7 \)? What does the graph look like?
5. How would the y-intercept change if the equation was \( y = x^2 + 2x - 3 \)?

**Tip:** When finding the y-intercept of an equation, always set \( x = 0 \).

Find the y-intercept of the following equation: y = x^2 + 2x + 7

Learn how to find the y-intercept of the quadratic equation y = x^2 + 2x + 7 by setting x to 0 and solving for y. This algebraic problem involves basic concepts of quadratic equations and intercepts, ideal for students in Grades 8-10.

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