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To find the **y-intercept** of the parabola given by the equation \( y = x^2 + 5x + 5 \), we need to substitute \( x = 0 \) into the equation because the y-intercept is the point where the graph intersects the y-axis, and on the y-axis, \( x = 0 \).

Let's substitute:

\[
y = (0)^2 + 5(0) + 5
\]

\[
y = 5
\]

Thus, the **y-intercept** is \( \boxed{5} \).

Would you like more details or explanations? Here are some related questions to expand on this concept:

1. How do you find the x-intercepts of the same parabola?
2. What is the vertex of this parabola?
3. How do you determine if the parabola opens upwards or downwards?
4. Can the equation of the parabola be factored?
5. What is the axis of symmetry for the parabola?

**Tip:** The coefficient of the \( x^2 \) term in a quadratic equation determines whether the parabola opens upwards (positive coefficient) or downwards (negative coefficient).

Find the y-intercept for the parabola whose equation is y = x^2 + 5x + 5.

Learn how to find the y-intercept of the quadratic equation y = x^2 + 5x + 5 by substituting x = 0. This problem covers key algebraic concepts and quadratic functions, suitable for students in Grades 8-10.

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