Math Problem Statement

c. For online orders filled by the eastern​ DC, find the value a for which

​P(xgreater than>​a)equals=0.30.3.

enter your response here

​(Round to two decimal places as​ needed.)

Solution

The problem asks to find the value of aa for which the probability P(x>a)=0.3P(x > a) = 0.3.

This can be understood as finding a value of aa from a probability distribution where the upper tail probability (the area under the curve to the right of aa) is 0.3.

Let's assume the distribution follows a standard normal distribution, which is the most common in such problems unless specified otherwise.

In a normal distribution, the relationship between probabilities and values is determined by the Z-score (which corresponds to the value aa in this case).

Step-by-step process:

  1. We need to find the Z-score that corresponds to the probability P(x>a)=0.3P(x > a) = 0.3. This is the same as asking for P(x<a)=0.7P(x < a) = 0.7 because probabilities must sum to 1.

  2. Using a Z-table or a statistical calculator, the Z-score that corresponds to P(x<a)=0.7P(x < a) = 0.7 is approximately 0.524.

  3. Therefore, the value of aa is approximately 0.52.

So, the value of aa rounded to two decimal places is 0.52.

Would you like further details on this or have any other questions?


Here are five related questions that might interest you:

  1. How is the Z-score calculated for a given probability in a normal distribution?
  2. What is the difference between a Z-score and a T-score in statistics?
  3. How do we handle probabilities when the distribution is not normal?
  4. What are cumulative distribution functions (CDF) and how are they used?
  5. How do confidence intervals relate to Z-scores in hypothesis testing?

Tip: When solving probability problems, always check if the question assumes a normal distribution, unless stated otherwise!

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Math Problem Analysis

Mathematical Concepts

Probability
Normal Distribution
Z-Scores

Formulas

P(x > a) = 1 - P(x < a)
Z = (X - μ) / σ

Theorems

Empirical Rule
Standard Normal Distribution

Suitable Grade Level

Grades 10-12