We are having a physics test on forces and Universal Gravitation and the questions give is 15 N Net force, 12 Kg box, it want us to find the speed with 6 s interval?

To solve this problem, we need to apply concepts from Newton's Second Law of Motion and kinematics.

### Step 1: Find the acceleration
Newton's Second Law states that:

\[
F_{\text{net}} = m \cdot a
\]

Where:
- \( F_{\text{net}} = 15 \, \text{N} \) (net force)
- \( m = 12 \, \text{kg} \) (mass of the box)
- \( a \) is the acceleration

We can rearrange the formula to solve for acceleration \( a \):

\[
a = \frac{F_{\text{net}}}{m}
\]

Substituting the known values:

\[
a = \frac{15 \, \text{N}}{12 \, \text{kg}} = 1.25 \, \text{m/s}^2
\]

### Step 2: Find the final velocity (speed after 6 seconds)
Now that we have the acceleration, we can find the speed after 6 seconds using the kinematic equation:

\[
v = u + at
\]

Where:
- \( v \) is the final velocity (speed) after time \( t \)
- \( u \) is the initial velocity (if the box starts from rest, \( u = 0 \))
- \( a = 1.25 \, \text{m/s}^2 \) (acceleration)
- \( t = 6 \, \text{s} \) (time)

Substituting the values:

\[
v = 0 + (1.25 \, \text{m/s}^2)(6 \, \text{s}) = 7.5 \, \text{m/s}
\]

### Final Answer:
The speed of the box after 6 seconds is **7.5 m/s**.

---

Would you like further details or have any questions about the process?

Here are some related questions you might find helpful:
1. How does the direction of the net force affect the acceleration?
2. How do you calculate velocity if the object is not at rest at the start?
3. What would happen if the mass of the object increased but the same net force was applied?
4. How does friction affect the net force in this type of problem?
5. How do you use the Universal Gravitation formula to calculate gravitational force between two objects?

**Tip:** Always remember to check whether the object starts from rest or has an initial velocity, as it will affect how you calculate the final velocity.

Learn how to find the speed of a box after 6 seconds when a net force of 15 N is applied to a 12 kg box. The solution covers Newton's Second Law, acceleration, and kinematic equations. Suitable for students in Grades 9-10.

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