Math Problem Statement
The following stem-and-leaf plot represents the times in minutes required for 26 co-workers to commute to work. Use the data provided to find the quartiles.
Commute Times in Minutes Stem Leaves 1 0 4 4 6 6 6 9 2 2 4 4 5 8 3 3 4 4 5 6 8 4 0 0 3 3 5 6 7 8 Key: 1|0=10
Step 1 of 3 : Find the second quartile. Answer How to enter your answer (opens in new window)
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Solution
To find the second quartile (Q2), which is also known as the median, we need to follow these steps:
- List the data: Convert the stem-and-leaf plot into an ordered list of commute times.
- Determine the position of Q2: Since Q2 is the median, it will be at the position, where is the total number of data points.
- Find Q2: Identify the value corresponding to this position.
Step 1: List the Data
Let's convert the stem-and-leaf plot into an ordered list of the 26 commute times:
- Stem 1: 10, 14, 14, 16, 16, 16, 19
- Stem 2: 22, 24, 24, 25, 28
- Stem 3: 33, 34, 34, 35, 36, 38
- Stem 4: 40, 40, 43, 43, 45, 46, 47, 48
So, the ordered data set is:
Step 2: Determine the Position of Q2
- Total number of data points, .
- The position of the median (Q2) is at:
Step 3: Find Q2
- Since the position is 13.5, Q2 will be the average of the 13th and 14th data points in the ordered list.
- The 13th data point is 33, and the 14th data point is 34.
So, the second quartile (Q2) is:
Answer: The second quartile (Q2) is 33.5 minutes.
Would you like to calculate the other quartiles or have more details? Here are some additional questions:
- How do you find the first quartile (Q1) from this data?
- What is the third quartile (Q3) of the dataset?
- How do you calculate the interquartile range (IQR)?
- Can you identify any outliers based on the IQR?
- How does a stem-and-leaf plot help in understanding data distribution?
Tip: The median divides your data into two equal halves, making it a great measure of central tendency for skewed distributions.
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Math Problem Analysis
Mathematical Concepts
Descriptive Statistics
Quartiles
Formulas
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Theorems
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Suitable Grade Level
High School
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