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Let's solve the problem step by step.

### Problem Recap:
- A **rectangular playpen** must have:
  - **Perimeter** = 150 feet
  - **Area** ≥ 1000 square feet
- We are asked to **describe the possible lengths** of the playpen.

---

### 1. Perimeter Equation:
The perimeter \(P\) of a rectangle is given by:
\[
P = 2L + 2W
\]
where \(L\) is the length, and \(W\) is the width.

For this problem:
\[
2L + 2W = 150
\]
We can simplify:
\[
L + W = 75 \quad \text{(Equation 1)}
\]
So:
\[
W = 75 - L \quad \text{(solve for } W \text{ in terms of } L)
\]

---

### 2. Area Constraint:
The area \(A\) of the rectangle is:
\[
A = L \times W
\]
Using the expression for \(W\) from Equation 1:
\[
A = L \times (75 - L) \geq 1000
\]
Expanding:
\[
A = 75L - L^2 \geq 1000
\]
Rearrange:
\[
L^2 - 75L + 1000 \leq 0
\]

---

### 3. Solving the Quadratic Inequality:
First, solve the corresponding equation:
\[
L^2 - 75L + 1000 = 0
\]
Using the quadratic formula:
\[
L = \frac{-(-75) \pm \sqrt{(-75)^2 - 4(1)(1000)}}{2(1)}
\]
\[
L = \frac{75 \pm \sqrt{5625 - 4000}}{2}
\]
\[
L = \frac{75 \pm \sqrt{1625}}{2}
\]
\[
\sqrt{1625} \approx 40.31
\]
\[
L = \frac{75 \pm 40.31}{2}
\]
So:
\[
L = \frac{75 + 40.31}{2} \approx 57.66 \quad \text{and} \quad L = \frac{75 - 40.31}{2} \approx 17.34
\]

---

### 4. Length Range:
The solutions to the quadratic equation are \(L \approx 17.34\) and \(L \approx 57.66\). Since the quadratic opens upward (positive \(L^2\) coefficient), the inequality \(L^2 - 75L + 1000 \leq 0\) holds between these two values.

Thus, the **possible lengths** are:
\[
17.34 \leq L \leq 57.66
\]

---

### Final Answer:
The length of the playpen must be **at least 17.34 feet** and **at most 57.66 feet**.

---

Do you want further clarification on any step or need more examples?

Here are 5 follow-up questions to deepen your understanding:
1. How would the dimensions change if the perimeter was 160 feet instead of 150?
2. What happens if the required area is increased to 1200 square feet?
3. Can you determine the exact width for the minimum and maximum lengths found?
4. How does changing only the width affect the area and perimeter?
5. Can you verify the answer by substituting the limits back into the perimeter and area formulas?

**Tip:** Always try to sketch a quick graph when working with quadratic inequalities to visualize the solution.

An animal shelter director is planning to build a rectangular playpen. The playpen must have a perimeter of 150 feet and an area of at least 1000 square feet. Describe the possible lengths of the playpen.

Solve a problem where the perimeter of a rectangular playpen is 150 feet and the area must be at least 1000 square feet. Learn how to apply algebraic methods, including solving a quadratic equation, to find the possible lengths of the playpen.

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