Math Problem Statement

If n(Ax B) = 667 and n(B) = 29,

find n(A)

Solution

The given information states:

  • n(A×B)=667n(A \times B) = 667 (the number of elements in the Cartesian product A×BA \times B)
  • n(B)=29n(B) = 29 (the number of elements in set BB)

Formula for Cartesian Product:

n(A×B)=n(A)×n(B)n(A \times B) = n(A) \times n(B)

Substituting the values:

667=n(A)×29667 = n(A) \times 29

Solving for n(A)n(A):

n(A)=66729=23n(A) = \frac{667}{29} = 23

Thus, n(A)=23n(A) = 23.

Would you like a deeper explanation or have any questions?

Related Questions:

  1. What is the Cartesian product of two sets, and how is it defined?
  2. If n(A)=15n(A) = 15 and n(B)=40n(B) = 40, what is n(A×B)n(A \times B)?
  3. How does the Cartesian product behave when one of the sets is empty?
  4. If n(A×B)=900n(A \times B) = 900 and n(A)=30n(A) = 30, find n(B)n(B).
  5. What are the practical applications of Cartesian products in mathematics?

Tip:

When working with set operations, always verify whether the sets involved are finite or infinite to ensure calculations make sense!

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Math Problem Analysis

Mathematical Concepts

Set Theory
Cartesian Product

Formulas

n(A x B) = n(A) * n(B)

Theorems

Cartesian Product Theorem

Suitable Grade Level

Grades 9-11