Math Problem Statement
Consider the function f(x)=3/4x^4-x^3-9x^2+20 (a) Find f(-2) (b) Find f'(x) The graph of the function f has a local minimum at the point where x=-2 (c) Using your answer to part (b), show that there is a second local minimum at x = 3
Solution
Let’s solve the parts step-by-step:
(a) Find
Given the function:
Substitute into the function:
Simplify each term:
Now plug everything into the expression:
Thus,
(b) Find
We differentiate .
Apply the power rule: .
Simplify:
Thus,
(c) Show that there is a second local minimum at
To check for local minima, we need to find the critical points by setting .
Factor out :
Solve the quadratic inside the parentheses:
Factor:
So, the solutions are:
These are the critical points. Since we are given that there is a local minimum at , we now check whether also corresponds to a local minimum.
Second Derivative Test
We use the second derivative to determine if the function has a local minimum at .
Start by finding .
Differentiate .
Now evaluate at :
Simplify:
Since , the function is concave up at . Therefore, there is a local minimum at .
Final Answer Summary
- (a)
- (b)
- (c) There is a second local minimum at since , indicating concave up.
Do you have any questions or need further details?
Here are five related questions to explore:
- What is the value of ?
- How would the function behave as or ?
- Can you graph the function to visualize the local minima and maxima?
- How do you find points of inflection for the function?
- What are the x-intercepts of the original function ?
Tip: Always verify the sign of the second derivative at critical points to determine if it’s a local minimum or maximum.
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Math Problem Analysis
Mathematical Concepts
Calculus
Differentiation
Critical Points
Second Derivative Test
Formulas
Power rule: d/dx(x^n) = nx^(n-1)
Second derivative test: If f''(x) > 0 at a critical point, it is a local minimum
Theorems
Second Derivative Test
Suitable Grade Level
Grades 11-12
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