Math Problem Statement

Solve

Find the coordinates of the points of intersection of the graphs with the coordinate axes. Also, find the x- and y-intercepts for the given equations, construct graphs, and graph the points that satisfy the equation x=2.

Solution

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Ch. 3: 104

Find the coordinates of the points of intersection of the graphs with the coordinate axes for the following equations:

a. y=1.5x+3y = -1.5x + 3

To find the intersection with the axes, we need the points where the graph crosses the xx-axis and the yy-axis:

  • Intersection with the yy-axis: Set x=0x = 0. y=1.5(0)+3=3y = -1.5(0) + 3 = 3 So, the intersection with the yy-axis is at (0,3)(0, 3).

  • Intersection with the xx-axis: Set y=0y = 0. 0=1.5x+30 = -1.5x + 3 1.5x=3x=21.5x = 3 \quad \Rightarrow \quad x = 2 So, the intersection with the xx-axis is at (2,0)(2, 0).

e. y=0.8x0.6y = 0.8x - 0.6

  • Intersection with the yy-axis: Set x=0x = 0. y=0.8(0)0.6=0.6y = 0.8(0) - 0.6 = -0.6 So, the intersection with the yy-axis is at (0,0.6)(0, -0.6).

  • Intersection with the xx-axis: Set y=0y = 0. 0=0.8x0.60 = 0.8x - 0.6 0.8x=0.6x=0.60.8=0.750.8x = 0.6 \quad \Rightarrow \quad x = \frac{0.6}{0.8} = 0.75 So, the intersection with the xx-axis is at (0.75,0)(0.75, 0).

Ch. 3: 103

Find the xx- and yy-intercepts for the following equations:

f. 3x2y=03x - 2y = 0

  • Intersection with the yy-axis: Set x=0x = 0. 3(0)2y=02y=0y=03(0) - 2y = 0 \quad \Rightarrow \quad -2y = 0 \quad \Rightarrow \quad y = 0 So, the intersection with the yy-axis is (0,0)(0, 0).

  • Intersection with the xx-axis: Set y=0y = 0. 3x2(0)=03x=0x=03x - 2(0) = 0 \quad \Rightarrow \quad 3x = 0 \quad \Rightarrow \quad x = 0 So, the intersection with the xx-axis is (0,0)(0, 0).

g. 2x+5y11=02x + 5y - 11 = 0

  • Intersection with the yy-axis: Set x=0x = 0. 2(0)+5y11=05y=11y=115=2.22(0) + 5y - 11 = 0 \quad \Rightarrow \quad 5y = 11 \quad \Rightarrow \quad y = \frac{11}{5} = 2.2 So, the intersection with the yy-axis is (0,2.2)(0, 2.2).

  • Intersection with the xx-axis: Set y=0y = 0. 2x+5(0)11=02x=11x=112=5.52x + 5(0) - 11 = 0 \quad \Rightarrow \quad 2x = 11 \quad \Rightarrow \quad x = \frac{11}{2} = 5.5 So, the intersection with the xx-axis is (5.5,0)(5.5, 0).

Ch. 3: 107

Construct graphs for the equations:

c. y=14y = \frac{1}{4}

This is a horizontal line where the value of yy is always 14\frac{1}{4}. The line intersects the yy-axis at (0,14)(0, \frac{1}{4}) and runs parallel to the xx-axis.

3044: Graph all points that satisfy the given equation.

c. x=2x = 2

This is a vertical line where the value of xx is always 2. The line intersects the xx-axis at (2,0)(2, 0) and runs parallel to the yy-axis.


Would you like to go over any of these steps in more detail, or do you have any other questions? Here's some related exploration:

  1. How would you graph a linear equation when you know the intercepts?
  2. What happens if the slope is zero or undefined in an equation?
  3. Can you solve systems of equations using intercepts?
  4. How does the slope of a line affect its intersections with the axes?
  5. What if the graph of the equation is not a straight line?

Tip: Always start by finding the intercepts (where the graph crosses the axes) to quickly sketch the graph of a line!

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Intercepts
Graphing Linear Equations
Solving Systems of Equations

Formulas

y = mx + b
x-intercept: y = 0
y-intercept: x = 0

Theorems

Intercept Theorem
Graphing of Linear Equations

Suitable Grade Level

Grades 8-10