To find $h(3)$ for the function $h(x) = |5x - 17|$, follow these steps:

1. Substitute $x = 3$ into the expression for $h(x)$: $h(3) = |5(3) - 17|$

2. Simplify inside the absolute value: $h(3) = |15 - 17| = |-2|$

3. The absolute value of -2 is 2: $h(3) = 2$

Thus, $h(3) = 2$.

Would you like further details or explanations on this? Here are some related questions for deeper understanding:

1. How do absolute value functions work in general?
2. What happens if the expression inside the absolute value is positive or zero?
3. Can absolute value functions be solved graphically?
4. How would you solve $h(x) = 10$ for $h(x) = |5x - 17|$?
5. What is the behavior of $h(x) = |5x - 17|$ as $x$ approaches large values?

Tip: When dealing with absolute values, always break down the expression into two cases: one for the positive value and one for the negative value.