Math Problem Statement

A hill makes an angle of 20° with the horizontal. On the hill stood an old, wobbly, wooden, 50-foot tall watch tower that was starting to lean. A guy wire was attached to the top of the watch tower and secured to a spot 80 feet uphill. The guy wire was tightened until the watch tower was standing perfectly vertical again. Additional braces were added to make sure the tower wobbled no more! How long was the guy wire?

A hill makes an angle of 20° with the horizontal. On the hill stood an old, wobbly, wooden, 50-foot tall watch tower that was starting to lean. A guy wire was attached to the top of the watch tower and secured to a spot 80 feet uphill. The guy wire was tightened until the watch tower was standing perfectly vertical again. Additional braces were added to make sure the tower wobbled no more! How long was the guy wire?

Solution

To solve this problem, let's analyze the given scenario using trigonometry. Here's how we can proceed:

Given:

  • The hill makes an angle of 2020^\circ with the horizontal.
  • The watch tower is 5050 feet tall and is now vertical.
  • The guy wire is attached to the top of the tower and is secured 8080 feet uphill.
  • We need to find the length of the guy wire.

Solution:

  1. Visualize the Triangle:

    • The guy wire, the height of the tower, and the horizontal distance uphill form a right triangle.
    • Since the hill is inclined at 2020^\circ, we need to adjust the position of the tower so it stands vertical. When the guy wire is attached, it forms a triangle where:
      • The height of the triangle is the height of the tower (5050 feet).
      • The base of the triangle will be the horizontal component of the distance uphill.
      • The hypotenuse of the triangle is the guy wire (which we need to find).
  2. Decomposing the Lengths:

    • The 8080 feet uphill distance is not horizontal but along the slope of the hill. To find the horizontal component, we need to use: x=80cos(20)x = 80 \cos(20^\circ) where xx is the horizontal distance from the base of the tower to where the guy wire is secured.
  3. Use Pythagoras' Theorem:

    • The guy wire, LL, is the hypotenuse of the right triangle: L2=502+x2L^2 = 50^2 + x^2
  4. Calculation: First, calculate the horizontal distance xx: x=80cos(20)75.18 feetx = 80 \cos(20^\circ) \approx 75.18 \text{ feet}

    Now, use Pythagoras' theorem to find LL: L=502+75.182L = \sqrt{50^2 + 75.18^2} L=2500+5651.68L = \sqrt{2500 + 5651.68} L=8151.6890.31 feetL = \sqrt{8151.68} \approx 90.31 \text{ feet}

Conclusion:

The length of the guy wire is approximately 90.3190.31 feet.

Would you like more details or explanations on any part of this solution?

Related Questions:

  1. How would the solution change if the angle of the hill was 3030^\circ instead of 2020^\circ?
  2. Can you determine the tension in the guy wire if the tower exerts a force of 500 N vertically down?
  3. How would you calculate the force components acting along the hill's incline due to the guy wire?
  4. What if the guy wire was attached to a point 60 feet uphill instead of 80 feet?
  5. Could you determine the angle at which the guy wire makes with the hill's surface?

Tip:

When dealing with inclined planes, always decompose vectors and distances into components parallel and perpendicular to the incline. This helps in simplifying the calculation and ensures accuracy.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangle
Pythagorean Theorem

Formulas

Horizontal distance: x = 80 cos(20°)
Pythagoras' theorem: L² = height² + horizontal distance²

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-12