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To solve this question:

The equation given is \( y = 3 - 4x \).

In this equation, the general form for a straight line is \( y = mx + c \), where:
- \( m \) is the gradient (or slope) of the line,
- \( c \) is the y-intercept (the point where the line crosses the y-axis).

Comparing \( y = 3 - 4x \) to \( y = mx + c \), we see that:
- \( m = -4 \).

Therefore, the gradient of line \( L \) is **-4**.

Would you like further details or have any questions?

Here are some related questions for further practice:
1. What is the y-intercept of the line \( y = 3 - 4x \)?
2. How would you rewrite \( y = 3 - 4x \) in the form \( ax + by = c \)?
3. What is the gradient of a line parallel to \( y = 3 - 4x \)?
4. How would you find the gradient of a line perpendicular to \( y = 3 - 4x \)?
5. If \( y = 3 - 4x \) represents a road incline, what does a gradient of -4 indicate about its direction?

**Tip:** The gradient of a line indicates the steepness and direction of the slope; a negative gradient means the line slopes downwards.

The equation of a straight line L is y = 3 - 4x. Write down the gradient of L.

Learn how to find the gradient of a straight line with the equation y = 3 - 4x. This problem covers key linear equation concepts and demonstrates the use of the slope-intercept form.

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