To solve this question:

The equation given is $y = 3 - 4x$.

In this equation, the general form for a straight line is $y = mx + c$, where:

• $m$ is the gradient (or slope) of the line,
• $c$ is the y-intercept (the point where the line crosses the y-axis).

Comparing $y = 3 - 4x$ to $y = mx + c$, we see that:

• $m = -4$.

Therefore, the gradient of line $L$ is -4.

Would you like further details or have any questions?

Here are some related questions for further practice:

1. What is the y-intercept of the line $y = 3 - 4x$?
2. How would you rewrite $y = 3 - 4x$ in the form $ax + by = c$?
3. What is the gradient of a line parallel to $y = 3 - 4x$?
4. How would you find the gradient of a line perpendicular to $y = 3 - 4x$?
5. If $y = 3 - 4x$ represents a road incline, what does a gradient of -4 indicate about its direction?

Tip: The gradient of a line indicates the steepness and direction of the slope; a negative gradient means the line slopes downwards.