To find a fraction whose square root lies between 2 and 3, we need to find a fraction $\frac{a}{b}$ such that:

$2 < \sqrt{\frac{a}{b}} < 3$

Squaring all sides of the inequality:

$4 < \frac{a}{b} < 9$

Now we just need to find a fraction $\frac{a}{b}$ that lies between 4 and 9. One possible solution is:

$\frac{a}{b} = \frac{20}{5} = 4.8$

Since $\frac{20}{5} = 4.8$, we can check its square root:

$\sqrt{\frac{20}{5}} = \sqrt{4.8} \approx 2.19$

This satisfies the condition that the square root is between 2 and 3.

Would you like further clarification or other examples?

Here are 5 related questions:

1. What is the square root of 7/2?
2. How do you find the square root of a decimal number?
3. Can you find another fraction whose square root is between 2 and 3?
4. How do you simplify the square root of a fraction?
5. How would you solve inequalities involving square roots?

Tip: When solving inequalities involving square roots, squaring both sides simplifies the problem but remember to check the validity of the solution afterward.