Math Problem Statement

Find an equation for the graph shown below. (Hint: use the form y = a(x - h)^2 + k)

Solution

To find the equation of the parabola shown, we'll use the vertex form of a quadratic function:

y=a(xh)2+ky = a(x - h)^2 + k

where:

  • (h,k)(h, k) is the vertex of the parabola,
  • aa determines the direction and width of the parabola.

Step 1: Determine the Vertex

From the graph:

  • The vertex appears to be at (3,1)(-3, -1), so h=3h = -3 and k=1k = -1.

Step 2: Substitute the Vertex into the Equation

Substitute h=3h = -3 and k=1k = -1:

y=a(x+3)21y = a(x + 3)^2 - 1

Step 3: Find the Value of aa

To determine aa, we need another point on the parabola. Observing the graph, it appears that the point (4,0)(-4, 0) lies on the curve.

Substitute x=4x = -4 and y=0y = 0 into the equation:

0=a(4+3)210 = a(-4 + 3)^2 - 1 0=a(1)210 = a(1)^2 - 1 0=a10 = a - 1 a=1a = 1

Final Equation

With a=1a = 1, the equation of the parabola is:

y=(x+3)21y = (x + 3)^2 - 1

Would you like more details on any specific step?


Related Questions

  1. How can we confirm the values of hh and kk for a vertex form equation?
  2. What happens if aa is negative in the vertex form?
  3. How would you transform this parabola if you wanted it to open downward?
  4. How can you find the axis of symmetry from the vertex form equation?
  5. What is the role of the value of aa in changing the parabola's shape?

Tip

Remember, the sign of hh in the equation (xh)(x - h) is opposite to the xx-value of the vertex.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Parabola
Vertex Form of a Quadratic Equation

Formulas

y = a(x - h)^2 + k

Theorems

Vertex form of a quadratic equation

Suitable Grade Level

Grades 9-11