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The table you provided shows the following values for \(x\) and \(y\):

\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
15 & 45 \\
1  & 0  \\
\hline
\end{array}
\]

It seems you're dealing with two sets of coordinates: \( (15, 45) \) and \( (1, 0) \). One possible interpretation is that these values represent points on a linear relationship. If you're trying to find the equation of the line passing through these points, you can use the formula for the slope of a line:

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Substituting the values \( (x_1, y_1) = (15, 45) \) and \( (x_2, y_2) = (1, 0) \):

\[
m = \frac{0 - 45}{1 - 15} = \frac{-45}{-14} = \frac{45}{14}
\]

So, the slope of the line is \( m = \frac{45}{14} \).

Next, use the point-slope form to find the equation of the line:

\[
y - y_1 = m(x - x_1)
\]

Substituting \( m = \frac{45}{14} \), \( x_1 = 15 \), and \( y_1 = 45 \):

\[
y - 45 = \frac{45}{14}(x - 15)
\]

This simplifies to the equation of the line.

Do you have any questions about this solution? Would you like more details or additional assistance?

### Related Questions:
1. How do you find the y-intercept from the equation of a line?
2. Can we use this method for other types of functions, like quadratic or exponential functions?
3. How do you determine whether a function is linear from a table of values?
4. What happens to the slope if we switch the order of the points?
5. How can you calculate the slope if one of the points is the origin?

**Tip:** When dealing with a table of values, always check if the pattern between \(x\) and \(y\) is linear by calculating the slope between multiple pairs of points.

The user provided a table with two sets of values for x and y, where x = 15, y = 45, and x = 1, y = 0.

Learn how to calculate the equation of a line passing through two points (15, 45) and (1, 0). This problem involves finding the slope and using the point-slope form of a line. Suitable for students in Grades 8-10.

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