Math Problem Statement

cari domain dan range

cari domain dan range

Solution

The equation shown in the image is:

y=x2+2y = x^2 + 2

To find the domain and range:

Domain:

The domain of a function is the set of all possible input values (i.e., xx-values). In this case, since there are no restrictions on xx (like square roots or denominators that could make the expression undefined), the domain is:

Domain: (,)orR\text{Domain: } (-\infty, \infty) \quad \text{or} \quad \mathbb{R}

Range:

The range of a function is the set of all possible output values (i.e., yy-values). The given equation is a quadratic function of the form y=x2+2y = x^2 + 2. The graph of y=x2+2y = x^2 + 2 is a parabola that opens upwards, with its vertex at y=2y = 2 (since the minimum value of x2x^2 is 0, and x2+2x^2 + 2 will always be greater than or equal to 2).

Thus, the range is:

Range: [2,)\text{Range: } [2, \infty)

Would you like further details or explanations on these steps?

Related Questions:

  1. How can we graph the function y=x2+2y = x^2 + 2?
  2. How do we determine if a function is one-to-one or onto?
  3. What would be the effect of changing the equation to y=x22y = x^2 - 2?
  4. How can we find the vertex of a quadratic function?
  5. What are the differences between domain and range in other types of functions?

Tip: For quadratic functions in the form y=ax2+bx+cy = ax^2 + bx + c, the vertex and direction of the parabola can help determine the range!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions

Formulas

y = x^2 + 2
Domain and Range of a Function

Theorems

Basic properties of quadratic functions

Suitable Grade Level

Grades 7-10